C. Echolocation
Echolocating animals emit calls out to the environment and listen to the echoes of those calls that return from various objects near them. They use these echoes to locate and identify the objects.
The mass attached to the spring must be 0.72 kg
Explanation:
The frequency of vibration of a spring-mass system is given by:
(1)
where
k is the spring constant
m is the mass attached to the spring
We can find the spring constant by using Hookes' law:

where
F is the force applied on the spring
x is the stretching of the spring
When a mass of m = 2.82 kg is applied to the spring, the force applied is the weight of the mass, so we have

and using
and
, we find

Now we want the frequency of vibration to be
f = 7.42 Hz
So we can rearrange eq.(1) to find the mass m that we need to attach to the spring:

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The frequency of the other wave is 613 Hz or 607 Hz.
The difference between the frequencies of two waves is called the beat frequency.
Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.
Which has a higher frequency is not mentioned. Therefore, there are two possibilities.
Δf = | 610 - 613 | = 3
or
Δf = | 610 - 607 | = 3
Therefore, the frequency of the other wave is 613 Hz or 607 Hz.
Learn more about beat frequency here:
brainly.com/question/14157895
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The equilibrant force of the two given forces is 14.14 N.
<h3 /><h3 /><h3>What is equilibrant force?</h3>
- This is a single force that balances other given forces.
The given parameters:
- First force, F₁ = 10 N
- Second force, F₂ = 10 N
- Angle between the forces, θ = 90⁰
The equilibrant force of the two given forces is calculated as follows;

Thus, the equilibrant force of the two given forces is 14.14 N.
Learn more about equilibrant force here: brainly.com/question/8045102