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mario62 [17]
3 years ago
6

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio

n between adjacent bright fringes on a screen 5 m from the slits is: CONVERT FIRST
Physics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

Δx = 2.5 x 10⁻³ m = 2.5 mm

Explanation:

The distance between two consecutive fringes, also known as fringe spacing, in Young's Double Slit Experiment, is given as follows:

Δx = λL/d

where,

Δx = distance between consecutive fringes = ?

λ = wavelength of light = 500 nm = 5 x 10⁻⁷ m

L = Distance between slits and screen = 5 m

d = slit separation = 1 mm = 1 x 10⁻³ m

Therefore,

Δx = (5 x 10⁻⁷ m)(5 m)/(1 x 10⁻³ m)

<u>Δx = 2.5 x 10⁻³ m = 2.5 mm</u>

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