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I am Lyosha [343]
3 years ago
14

the car starts from a stop to travel 1100 meters in 14 seconds. it is clocked at 65 m/s at point k. find its average speed and a

cceleration ​
Physics
1 answer:
inysia [295]3 years ago
4 0

Answer:

The average velocity of the car is, V = 74.04 m/s

Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

The displacement of the ca, S = 1100 m

The time period of travel, t = 14 s

The velocity of the car at point k, v = 65 m/s

Using the II equation of motion,

                      S = ut + ½  at²

Substituting the given values,

                      1100 = 0 + ½ x a x 14²

                          a = 11.22 m/s²

Using the III equation of motion

                         v² = u² + 2 as

                          v = √(2as)              (∵ u = 0)

Substituting,

                           v = √(2 x 11.22 x 1100)

                              = 157.11 m/s

The average speed of the car,

                        V=\frac{0+65+157.11}{3}

                        V = 74.04 m/s

Hence, the average velocity of the car is, V = 74.04 m/s

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Answer:

v = 2 m/s

Explanation:

The object moves 20 m in 10 s initially. Then it remains at rest for 20 s. It is required to find the average speed of the object.

Fro 10 s it covers 20 m. For that time, speed is :

v=\dfrac{d}{t}\\\\v=\dfrac{20\ m}{10\ s}\\\\v=2\ m/s

For 20 s, it was at rest means distance covered is 0. So, speed is 0.

The average speed of the object is equal to the sum of speed for 10 s and for 20 s i.e.

v = 2 m/s + 0 = 2 m/s

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A rock thrown with a horizontal velocity of 20m/s from a cliff that is 125m above level ground. If air resistance is negligible,
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Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor
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The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical anglei_{c} is related to the refractive index of the material of glass μ as shown below.

\mu =\frac{1}{sini_c}

For a refractive index equal to 1.5, the critical angle is found as shown below.

sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666

Take the inverse of the value 0.666 to determine the critical angle.

sin^{-1} (0.666)=41.8^o

The critical angle in air is less than the angle of incidence, and hence total internal reflection occurs in air.

When the binoculars are immersed in water, the ray passes into the glass through water. therefore, the refractive index of the prism when immersed in water is given by,

\mu_g_w=\frac{\mu_g}{\mu_w}

Therefore the critical angle <em>c</em> in this case is given by,

sinc=\frac{\mu_w}{\mu_g}

Substitute 1.33 for \mu_w and 1.5 for \mu_g.

sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866

Take the inverse of the value 0.8866.

c=sin^{-1} (0.8866)\\ =62^o

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.

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