Answer:
Explanation:
This is a circular motion questions
Where the oscillation is 27.3days
Given radius (r)=3.84×10^8m
Circular motion formulas
V=wr
a=v^2/r
w=θ/t
Now, the moon makes one complete oscillation for 27.3days
Then, one complete oscillation is 2πrad
Therefore, θ=2πrad
Then 27.3 days to secs
1day=24hrs
1hrs=3600sec
Therefore, 1day=24×3600secs
Now, 27.3days= 27.3×24×3600=2358720secs
t=2358720secs
Now,
w=θ/t
w=2π/2358720 rad/secs
Now,
V=wr
V=2π/2358720 ×3.84×10^8
V=1022.9m/s
Then,
a=v^2/r
a=1022.9^2/×3.84×10^8
a=0.0027m/s^2
Answer:
D. (7 ÷ 9) × 100
Explanation:
In order to solve this problem we need the answers of the problem, performing an internet search this problem is found, with the different answer options
A. (7 − 9) × 100
B. (9 − 7) × 100
C. (9 ÷ 7) × 100
D. (7 ÷ 9) × 100
Returning to the problem of the total energy of 9V only 7 volts were used. If we make a rule of three we realize that:
x = 77.77%
In this way we determine that the answer is D.
Answer:
c-) both objects will reach the bottom at the same instant.
(b) decrease.
Explanation:
Although the feather is lighter than the coin, the tube where the experiment is performed is evacuated. Therefore there is no air that prevents the feather from falling freely with the same acceleration and speed as the coin.
In fact in the equations of kinematics proposed by Newton, the mass of the bodies is not taken into account, as we can see in the following equation:
where:
Vf = final velocity [m/s]
Vi = initial velocity [m/s]
g = gravity acceleration [m/s^2]
t = time [s]
Therefore the answer is C.
Gravitational pull is a function of height, as the height of the body increases, the force of gravity decreases.
when the reflected rays of the mirror meets
Explanation:
When two incident rays go and strike to the mirror, their reflected rays meet and image is formed
Out of the choices given, when a light wave moves from a medium where particles of matter are closely packed to a medium made of little matter. You expect the light wave to move faster and increase its speed.