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motikmotik
3 years ago
15

Solve: A car travels 2 km North , 10 km East, then 3 km West. pythagorean theorem

Physics
1 answer:
Evgen [1.6K]3 years ago
5 0

________b_____ 7 km east

|

| 2km north.

|a

|

°

pythagorean theorem : ✓a² + b² = c²

c² = a² + b² = 4 + 49 = 53

c = ✓53 km

displacement = c = ✓53 km

distance = 10 + 3 + 2 = 15 km

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The driver sees that the road is empty and accelerates at 1.0 m/s2 for 5.0 s. what can you determine about the truck's motion us
vekshin1

kinematic equation

v=u+at

v-u=at

v-u = 1x5

the driver will have increased speed by 5 m/s. actual speeds unknown

7 0
3 years ago
A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2

So, the acceleration of the hockey puck is 190\ m/s^2.

5 0
3 years ago
Two concrete spans of a 250-m-long bridge are placed end to end so that no room is allowed for expansion. If a temperature incre
scoundrel [369]

Answer:

  y = 2.74 m

Explanation:

The linear thermal expansion processes are described by the expression

         ΔL = α L ΔT

Where α the thermal dilation constant for concrete is 12 10⁻⁶ºC⁻¹, ΔL is the length variation and ΔT the temperature variation in this case 20ªc

If the bridge is 250 m long and is covered by two sections each of them must be L = 125 m, let's calculate the variation in length

        ΔL = 12 10⁻⁶ 125 20

        ΔL = 3.0 10⁻² m

Let's use trigonometry to find the height

The hypotenuse     Lf = 125 + 0.03 = 125.03 m

Adjacent leg           L₀ = 125 m

       cos θ = L₀ / Lf

       θ = cos⁻¹ (L₀ / Lf)

       θ = cos⁻¹ (125 / 125.03)

       θ = 1,255º

We calculate the height

       tan 1,255 = y / x

       y = x tan 1,255

       y = 125 tan 1,255

       y = 2.74 m

3 0
3 years ago
The speed of light in a vacuum is approximately 0.3 gm/s. What is the speed of light in meters per second?
klemol [59]

We have to convert Gm/s to m/s.

As  1 \ Gm/s = 10^9 \ m/s

Therefore the speed of light in vacuum,

c = 0.3 \ Gm/s = 0.3 \times 10^9 \ m/s \\\\ c= 3 \times 10^8 \ m/s

Thus, the speed of light in m/s is 3 \times 10^8 \ m/s

7 0
3 years ago
What is the speed of a wave with a wavelength of 10 mm and a frequency of 5.0 Hz?
sleet_krkn [62]
Speed = wavelength × frequency
speed = 10/1000 × 5.0
speed = 0.001 × 5.0
speed = 0.005m/s
4 0
3 years ago
Read 2 more answers
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