<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Answer:
The answer is (C)
Step-by-step explanation:
because unit cube, more formally a cube of side 1, is a cube whose sides are 1 unit long .The volume of a 3-dimensional unit cube is 1 cubic unit, and its total surface area is 6 square units.
Answer:
x=11
Step-by-step explanation:
5x+62=3x+47+37
5x+62=3x+84
2x=22
x=11
Answer:
Correct answer: Fourth answer As = 73.06 m²
Step-by-step explanation:
Given:
Radius of circle R = 16 m
Angle of circular section θ = π/2
The area of a segment is obtained by subtracting from the area of the circular section the area of an right-angled right triangle.
We calculate the circular section area using the formula:
Acs = R²· θ / 2
We calculate the area of an right-angled right triangle using the formula:
Art = R² / 2
The area of a segment is:
As = Acs - Art = R²· θ / 2 - R² / 2 = R² / 2 ( θ - 1)
As = 16² / 2 · ( π/2 - 1) = 256 / 2 · ( 1.570796 - 1) = 128 · 0.570796 = 73.06 m²
As = 73.06 m²
God is with you!!!
