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3 years ago

If you add 5.0 ml of 0.5 m naoh solution to 20.0 ml each of buffer b and buffer c, which buffer’s ph would change less? ex

1 answer:

8 0

If 5 ml of 0.5 M NaOH is added to 20 ml each of Buffer b and buffer c. Both of the buffers' pHs won't change since a buffer has a property that if it is added to another solution, acidic or basic, its pH won't change.

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Whats is a chemical change of a paper bag

DanielleElmas [232]

Combustion will cause a chemical change in paper.

This is because the carbon compounds are being oxidized into carbon dioxide and water vapour (or h2o, same thing).

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3 years ago

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_Al + _Fe(NO3)2 -->_Fe + __Al(NO3)3

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3 years ago

In which cell structure does MOST of the process of cellular respiration take place?

ahrayia [7]

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3 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

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3 years ago

When road contractors are laying cement,they first place a series of steel rods in a specific patterns. the they pour the cement

Anna11 [10]

The steel rods will enable the concrete to form without any bumps and it will add shape to the cement and strength, so no odd massive lumps are formed.

That is what I think anyways :)

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3 years ago

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