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3 years ago

If you add 5.0 ml of 0.5 m naoh solution to 20.0 ml each of buffer b and buffer c, which buffer’s ph would change less? ex

1 answer:

8 0

If 5 ml of 0.5 M NaOH is added to 20 ml each of Buffer b and buffer c. Both of the buffers' pHs won't change since a buffer has a property that if it is added to another solution, acidic or basic, its pH won't change.

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How many moles of oxygen atoms are in one mole of the molecule Ca5(PO4)3OH?

Ilya [14]

Answer:

Explanation:

There are 13 moles O in a mole of Ca5(PO4)3OH because there are 13 oxygen atoms in every molecule of Ca5(PO4)3OH. Convert moles oxygen to number of atoms of oxygen. One mole is 6.022*10^23, so your conversion factor would be 6.022*10^23 atoms O/mol O.

3 0

3 years ago

Proteins are polymers of _____. proteins are polymers of _____. ch2o units amino acids nucleotides glycerol hydrocarbons

sergey [27]

Proteins are polymers of amino acids.
The human body requires 20 amino acids which can be obtained by breaking down proteins. Out of the 20, 9 are essential amino acids which the human body cannot synthesize, and it is obtained only from food source.

6 0

3 years ago

Calculate the molarity of each of the following solutions.

Charra [1.4K]

Answer:

a)1.56 M

b) 0.376 M

c) 0.599 M

Explanation:

Step 1: Molarity

Molarity = Number of moles / volume in L

Number of moles = mass / Molar mass

(a) 7.49 g of methanol (CH3OH) in 1.50 * 10² mL of solution

Volume = 1.50 * 10² mL = 0.15 L

Molar mass of CH3OH = 32.04 g/mol

Number of moles CH3OH = 7.49 grams / 32.04 g/mol

Moles of CH3OH = 0.234 moles

Molarity CH3OH = 0.234 moles / 0.15 L

Molarity CH3OH = 1.56 M

(b) 9.18 g of calcium chloride (CaCl2) in 2.20 × 10² mL of solution:

Volume = 2.20 × 10² mL = 0.22L

Molar mass of CaCl2 = 110.98 g/mol

Number of moles CaCl2 = 9.18 grams /110.98 g/mol

Moles CaCl2 = 0.0827 moles

Molarity CaCl2 = 0.0827 moles / 0.22L

Molarity CaCl2 = 0.376 M

Volume = 85.2 mL = 0.0852L

Molar mass of C10H8 = 128.17 g/mol

Number of moles C10H8 = 6.51 grams / 128.17 g/mol

Moles C10H8 = 0.051 moles

Molarity C10H8 = 0.051 moles / 0.0852 L

Molarity C10H8 = 0.599 M

5 0

3 years ago

All of the alkali earth metals, Group 2, have two valence electrons. Which of these would represent the oxidation number of the

juin [17]

Your answer should be C.) +2. "All the elements in Group 2 have two electrons in their valence shells, giving them an oxidation state of +2."

Credits: https://chem.libretexts.org/Core/Inorganic_Chemistry/Descriptive_Chemistry/Elements_Organized_by_Blo...

Hopefully this has helped! :)

5 0

3 years ago

The Ksp equation Ksp = [Ag+]2[CO32-] is the solubility product constant for which reaction?

DanielleElmas [232]

The solubility product is calculated using the ions that are formed by the dissolution of a solid. Therefore, the reaction for this solubility product expression is:
Ag₂CO₃ → 2Ag⁺ + CO₃⁻²

8 0

3 years ago