The molarity of a solution is 0.909 M.
m(CaCl₂) = 82 g; mass of calcium chloride
M(CaCl₂) = 111 g/mol; molar mass of calcium chloride
n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)
n(CaCl₂) = 82 g ÷ 111 g/mol
n(CaCl₂) = 0.74 mol; amount of calcium chloride
V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride
c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)
c(CaCl₂) = 0.74 mol ÷ 0.812 L
c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride
Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.
More about molarity: brainly.com/question/26873446
#SPJ4
Answer:
1.) To convert between grams and moles, you would use the substance's molar mass. To go from grams to moles, divide the grams by the molar mass. 600 g58.443 g/mol = 10.27 mol of NaCl. It has been found that 1 mol of any gas at STP (Standard Temperature and Pressure = 0 °C and 1 atm) occupies 22.4 L
Answer:
25.907°C
Explanation:
In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C
The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.
Thus:
= heat of combustion of benzoic acid
= heat energy released to water
= heat energy released to the calorimeter
Therefore,
![-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})](https://tex.z-dn.net/?f=-m_%7Bcombust%7D%2AH_%7Bcombust%7D%20%3D%20%5Bm_%7Bwater%7D%2Ac_%7Bwater%7D%20%2B%20C_%7Bcalori%7D%5D%2A%28T_%7Bf%7D%20-%20T_%7Bi%7D%29)
1.056*26.42 = [0.987*4.18 + 6.66](
- 23.32)
27.8995 = [4.12566+6.660]( - 23.32)
( - 23.32) = 27.8995/10.7857 = 2.587
= 23.32 + 2.587 = 25.907°C
The answer for this would be 69.6
