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Brums [2.3K]
3 years ago
12

How are groundwater and surface water related?

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
7 0

Answer:

Surface water and groundwater systems are connected in most landscapes. It is the groundwater contribution that keeps streams flowing between precipitation events or after snowmelt. For a stream to gain water, the elevation of the water table in the vicinity of the stream must be higher than the stream water surface.

Explanation: hope it helps you

VLD [36.1K]3 years ago
6 0

Answer:

Surface water and groundwater systems are connected in most landscapes. ... It is the groundwater contribution that keeps streams flowing between precipitation events or after snowmelt. For a stream to gain water, the elevation of the water table in the vicinity of the stream must be higher than the streamwater surface.

Explanation:

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As an EPA scientist studying catalytic converters and urban smog, you want to find Kc for the following reaction: 2 NO2 (g) ⇋ N2
dmitriy555 [2]

Answer:

3500

Explanation:

The equilibrium constant of the reaction which has to be calculated is:-

2 NO2 (g) ⇋ N2(g) + 2 O2(g)

The given chemical equation follows:

1/2 N2 (g) + 1/2 O2 (g) ⇋ NO (g)

The equilibrium constant for the above equation is 0.004.

We need to calculate the equilibrium constant for the reverse equation of above chemical equation and also double of the above chemical equation, which is:

2NO (g) ⇋ N2 (g) + O2 (g)

The equilibrium constant for the reverse double reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{eq}'=(\frac{1}{0.004})^2  = 62500

The given chemical equation follows:

2NO2 (g) ⇋ 2NO (g) + O2 (g)

The equilibrium constant for the above equation is 0.056.

Thus, adding the both reaction gives the original reaction. So, equilibrium constant is:- 62500 x 0.056 = 3500

3 0
4 years ago
4 NH3 +5 02 +4NO + 6H2O<br> When 70.25 grams of NH3 react, how many moles of H20 are produced?
romanna [79]

Answer:

6.19 mol H₂O

Explanation:

  • 4 NH₃ + 5O₂ → 4NO + 6H₂O

First, we<u> convert 70.25 grams of NH₃ into moles</u>, using its<em> molar mass</em>:

  • 70.25 g ÷ 17 g/mol = 4.13 mol NH₃

Then we <u>convert 4.13 moles of NH₃ into moles of H₂O</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 4.13 mol NH₃ * \frac{6molH_2O}{4molNH_3} = 6.19 mol H₂O
5 0
3 years ago
Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

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4 0
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