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3 years ago

How are groundwater and surface water related?

Chemistry

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer:

Surface water and groundwater systems are connected in most landscapes. It is the groundwater contribution that keeps streams flowing between precipitation events or after snowmelt. For a stream to gain water, the elevation of the water table in the vicinity of the stream must be higher than the stream water surface.

Explanation: hope it helps you

VLD [36.1K]3 years ago

6 0

Answer:

Surface water and groundwater systems are connected in most landscapes. ... It is the groundwater contribution that keeps streams flowing between precipitation events or after snowmelt. For a stream to gain water, the elevation of the water table in the vicinity of the stream must be higher than the streamwater surface.

Explanation:

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G the normal range of the ph of blood is between 7.35 and 7.45; variations beyond this range have significant health implication

Fiesta28 [93]

Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.

When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.

On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.

The normal pH range of blood is given as 7.35 - 7.45 which is greater than 7. That means blood is slight basic in nature.

Let us find hydroxide ion concentration of blood.

$pH + pOH = 14$

$7.35 + pOH = 14$

$pOH = 6.65$

$pOH = - log [OH-]$

$[OH-] = 10^{-6.65}$

$[OH-] = 2.24 \times 10^{-7}$

Ionic product of water is written as,

$[H+] [OH-] = 1 \times 10^{-14}$

Let us plug in the calculated value of [OH-]

$[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M$

The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M

Calculation of [H+] for pH = 7.45

pOH = 6.55

[OH-] = 2.82 x 10⁻⁷

$[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M$

Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.

8 0

3 years ago

Where would I find the elements with 8 valence electrons which have no charge?

Ierofanga [76]

Answer:

No charge, meaning that they have a stable electronic configuration.

It is mostly found in group 0, also known as noble gases.

4 0

4 years ago

If the following reaction is carried out with 50.0g of Na2S and 35.0g of AgNO3, which is the limiting reactant?

topjm [15]

Yes and Na2s is it cause why not

8 0

3 years ago

A student makes several observations about a piece of iron. Which observation describes a chemical property of the iron?

Mama L [17]

Answer:

An example of a chemical property of iron would be that it is capable of combining with oxygen to form iron oxide, or rust.

Explanation:

You have no choice listed, so I provided an example.

6 0

3 years ago

A buffer made with 100.00 mL of 0.95 M lactic acid (Ka=1.4x10-4) and 200.00 mL of 0.50 M lactate has a final volume of 1.0 L. Wh

Art [367]

Answer:

3.77

Explanation:

The pH of a buffer can be calculated by Handerson-Halsebach equation:

pH = pKa+ log [A⁻]/[HA]

Where pKa = -logKa, [A⁻] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

In this case [A⁻] = concentration of lactate. Because the final volume will be the same, and [X] = mol/L, we can use the number of moles instead of the concentration.

nHA = 0.1 L * 0.95 mol/L = 0.095 mol

nA⁻ = 0.2 L * 0.5 mol/L = 0.1 mol

When HCl is added, it will dissociate in H⁺ and Cl⁻. H⁺ will react if A⁻ to form more HA, so the equilibrium will be shift. Because of that, the number of moles of HA will be the initial plus the number of moles of H⁺ added (which is equal to the number of moles of HCl), and the number of moles of A⁻ will be the initial less the number of moles of H⁺.

nH⁺ = nHCl = 0.015 L* 0.75 = 0.01125 mol

nA⁻ = 0.1 - 0.01125 = 0.08875 mol

nHA = 0.095 + 0.01125 = 0.10625 mol

pKa = -log(1.4*10⁻⁴) = 3.85

pH = 3.85 + log(0.08875/0.10625)

pH = 3.77

8 0

3 years ago

Read 2 more answers