a. 43.1 g
b. 38.2%
<h3>Further explanation</h3>
Given
32.5 grams of NaOH
Required
The theoretical yield of Na₂CO₃
The percent yield
Solution
Reaction
2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l)
mol NaOH :
= mass : MW
= 32.5 : 40 g/mol
= 0.8125
mol Na₂CO₃ from the equation :
= 1/2 x mol NaOH
= 1/2 x 0.8125
= 0.40625
a.
Mass Na₂CO₃ :
= mol x MW Na₂CO₃
= 0.40625 x 106 g/mol
= 43.0625≈43.1 g
b. % yield = (actual/theoretical) x 100%
%yield = 16.45/43.1 x 1005
%yield = 38.17%≈38.2%
<span>Sample #2 and sample #3 must have the equal volume as sample #1 ,if the masses of the both samples are equal to mass of sample #1.
Otherwise, the volume would vary if the masses are not equal.</span>
Answer:
Mg
Explanation:
If one were comparing just the neutral atoms Mg and S, the S atom would be smaller as both elements are in the same period and sulfur is more to the right
A tone that is lower in pitch is lower in what characteristic?=frequency
Answer:
<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>
Explanation:
This is how the vegetation affects the runoff:-
The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.
If the vegetation present is dense with there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact
