Becasue KE= 1/2 mv squared
KE= 1/2 (100) 12.5 sqaured
50 156.25 =
7812.5 < is your answer
Hopefully that makes sense and i did the math right....
The chemical formula for the product is RbBr.
The correct answer would be 0.1505 M/s. Given the rate of disapperance of HBr, we can easily calculate the rate of apearance of the products by looking at the coefficients of the substances in the reaction. In this case, for every two moles of HBr, 1 mole of Br2 is being produced so the reaction rate would be:
- 1/2 (r(HBr)) = rBr2
- 1/2 (-0.301) = rBr2
Rate of appearance of Br2 = 0.1505 M/s
Group 2 elements are the alkaline earth metals
