2 years ago

WILL GIVE BRAINLIEST if you find area of figure

Mathematics

1 answer:

Lyrx [107]2 years ago

5 0

Look at the picture.

$A_1=2\ in\cdot3\ in=6\ in^2\\\\A_2=(6\ in-2\ in)\cdot5\ in=4\ in\cdot5\ in=20\ in^2$

Area of the figure:

$A=A_1+A_2\to A=6\ in^2+20\ in^2=26\ in^2$

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What is the total area of the figure? (square inches)

Radda [10]

Answer:

Step-by-step explanation:

TOTAL SURFACE AREA = AREA OF SQUARE+2×(AREA OF TRIANGLE)

=(6×6)+2×(1/2×6×4)

=36+24=60 square inches

I hope it helped you

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1 year ago

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You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building

nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

$h=\sqrt{x^2+y^2}$

The rate of change for the distance between you and the elevator is given by:

$\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}$

$-16=\frac{dh}{dy}*\frac{dy}{dt}$

$\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\$

Applying the chain rule:

$u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}$

Therefore, at x=300 and y = 500, dy/dt is:

$-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s$

The elevator is descending at 18.66 ft/s.

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2 years ago

What are the possible lengths of side Ab in a triangle which the given side lengths of 3 and 5 cm?

natali 33 [55]

Answer:

Plug this in a calculator and the answer will pop up.

Step-by-step explanation:

$\sqrt{5^{2} +3^{2}$

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2 years ago

Will give 5 stars on your answer and a thank you.

DENIUS [597]

Answer:

the variable term is (t)

the answer is 13.50t

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1 year ago

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lapo4ka [179]

1/2 ÷ -3/7 = -7/6 The answer is -7/6

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2 years ago