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Arada [10]
4 years ago
6

You have 125 g of a certain seasoning and are told that it contains 70.0 g of salt. What is the peroentage of salt by mass in th

is seasoning?
Chemistry
2 answers:
Ket [755]4 years ago
6 0

\frac{70}{125}  \times 100 = 56\%
Valentin [98]4 years ago
6 0
<h2>Answer </h2>

Percentage of salt is 56%

<u>Explanation </u>

The total weight of seasoning = 125 g of a certain seasoning total weight of salt = 70.0 g of salt to find the percentage we have to divide the weight of salt with the weight of certain seasoning and multiply by 100 like percentage = salt * 100/weight total. Hence the salt = 70 g seasoning and  weight 125g.

Calculation are shown below:

70*100/125 = 70*4/5 = 14*4 = 56% in 125g seasoning, there is 56% of salt

Therefore, the answer is the percentage of salt mass is 56%.

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How many grams of barium sulfate, BaSO 4 , be precipitated when 2.25 moles of sodium sulfate , Na 2 SO 3 , reacts with an excess
gulaghasi [49]

Answer:

525.1 g of BaSO₄ are produced.

Explanation:

The reaction of precipitation is:

Na₂SO₄ (aq) + BaCl₂ (aq) →  BaSO₄ (s) ↓  +  2NaCl (aq)

Ratio is 1:1. So 1 mol of sodium sulfate can make precipitate 1 mol of barium sulfate.

The excersise determines that the excess is the  BaCl₂.

After the reaction goes complete and, at 100 % yield reaction, 2.25 moles of BaSO₄ are produced.

We convert the moles to mass: 2.25 mol . 233.38 g/mol = 525.1 g

The precipitation's equilibrium is:

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3 years ago
Which formed first: hydrogen nuclei or hydrogen atoms?
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5 0
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Read more on moles here:

brainly.com/question/15356425

Hope it helps

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2 years ago
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