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Arada [10]
3 years ago
6

You have 125 g of a certain seasoning and are told that it contains 70.0 g of salt. What is the peroentage of salt by mass in th

is seasoning?
Chemistry
2 answers:
Ket [755]3 years ago
6 0

\frac{70}{125}  \times 100 = 56\%
Valentin [98]3 years ago
6 0
<h2>Answer </h2>

Percentage of salt is 56%

<u>Explanation </u>

The total weight of seasoning = 125 g of a certain seasoning total weight of salt = 70.0 g of salt to find the percentage we have to divide the weight of salt with the weight of certain seasoning and multiply by 100 like percentage = salt * 100/weight total. Hence the salt = 70 g seasoning and  weight 125g.

Calculation are shown below:

70*100/125 = 70*4/5 = 14*4 = 56% in 125g seasoning, there is 56% of salt

Therefore, the answer is the percentage of salt mass is 56%.

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A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.6
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Answer:

\% m=40.46\%

Explanation:

Hello there!

in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2

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\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%

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