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3 years ago

Which pair of molecules has the strongest dipole-dipole interactions?

Chemistry

1 answer:

Art [367]3 years ago

4 0

Answer: NH3 and NH3

Explanation:

If hydrogen is bonded to a highly electronegative element, a strong dipole-dipole attraction is set up with strength ten times greater than normal dipole-dipole attractions, and it is crystal clear that electronegativity increase from left to right across the period and it decreases down the group. Nitrogen being electronegative more than Oxygen will exhibit a greater dipole-dipole attraction. As such, NH3 and NH3 is the right answer.

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. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temp

marin [14]

Answer:

The answer to your question is Pressure = 5 atm

Explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

V1P1 = V2P2

Solve for P2

P2 = V1P1/V2

Substitution

P2 = (0.5 x 1) / 0.1

Simplification

P2 = 0.5/0.1

Result

P2 = 5 atm

3 0

3 years ago

An airplane travels 200 km/h in 4 hours going to Zambales. What will be the distance and displacement?

Fofino [41]

Answer:

See explanation

Explanation:

Recall that;

Speed = Distance/time

Distance = Speed * time

Speed = 200 km/h

Time = 4 hours

Distance = 200 km/h * 4 hours = 800 kilometres

Displacement has to do with distance covered in a specified direction, in this case, the direction is towards Zambales.

Hence, the displacement is 800 kilometres towards Zambales.

7 0

3 years ago

23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate

Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We calculate the moles of HCl that reacted, using the volume used and the concentration:

32.27 mL ⇒ 32.27/1000 = 0.03227 L

0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we calculate the mass of NH₃ that was titrated, using its molecular weight:

3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

0.0592 / 12.949 * 100% = 0.4575%

Now we calculate the total mass of NH₃ in the diluted sample:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0

3 years ago

A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if $F= \frac{m* v^{2} }{r}$ , then:
 $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

6 0

4 years ago

Enter your answer in the provided box. To draw a Lewis structure, first add the number of outer (valence) electrons contributed

DIA [1.3K]

Answer:

14 is this value for a molecule of $CH_3Cl$ .

Explanation:

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

Number of total outer valence electrons is carbon = 4

Number of total outer valence electrons is hydrogen = 1

Number of total outer valence electrons is chlorine = 7

For total number of outer electrons is $CH_3Cl$

$=1\times 4+3\times 1+1\times 7=14$

14 is this value for a molecule of $CH_3Cl$ .

4 0

4 years ago