The correct response is C. Chlorine forms 1 covalent bond while Oxygen forms 2 covalent bonds.
Heat gained by ice cubes would be equal to the - heat lost by warm water
The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol
Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J
Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C
In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature:
q(ice/water) = - q(warm water)
moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1)
50.5 g / 18.0 g/mol = 2.81 mol
2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80)
16916 + 211.3T2 = -669.4 T2 + 53555
36639 = 880.7 T2
T2 = 41.6 C
Answer:
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
Explanation:
Step 1: Data given
Number of moles hydrogen gas (H2) = 1.24 moles
Volume of hydrogen gas (H2° = 27.8 L
The final volume is increas to 40.6 L
Step 2: Calculate the new number of moles
V1/n1 = V2/n2
⇒with V1 = the initial volume = 27.8 L
⇒with n1 = the initial number of moles H2 = 1.24 moles
⇒with V2 = the final volume = 40.6 L
⇒with n2 = the new number of moles = TO BE DETERMINED
27.8L / 1.24 moles = 40.6 L / n2
n2 = 40.6 / (27.8/1.24)
n2= 1.81 moles
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
Answer:
The potential energy is 9800 J.
Explanation:
given information:
mass, m = 50 kg
height, h = 20 m
to calculate the potential energy, we can use the following formula
PE = mgh
where
PE = potential energy (Joule)
m = mass (kg)
h = height (m)
g = gravitational constant (9.8 m/s²)
so,
PE = mgh
= 50 x 9.8 x 20
= 9800 J
The octet rule signifies towards the capability of the atoms to prefer to exhibit eight electrons in the valence shell. In case, when the atoms possess lesser than eight electrons, they seem to react and produce more stable components. While discussing octet rule, one does not consider d or f electrons.
According to the octet rule, the atoms of the prime-group elements seem to bind in such a manner that each atom exhibit eight electrons in its valence shell, providing it the similar electronic configuration as a noble gas.
In the given question, in BrF3, fluorine follows octet rule, while bromine does not follow the octet rule.