Answer:
7
Explanation:
This question is a neutralization reaction.
50 ml of 0.125 M of KOH = (50 x 0.125) = 6.25 ml
In this same way, 50 ml of 0.125M of HCl = 50x0.125
= 6.25 ml
Then KOH is going to neutralise the HCl fully suvh that the pH of the medium is going to be 7
(H+) + (OH-) = H2O
Then Kw = [H=][OH-]
= [H+]² = 10^-14
Such that [H+] = 10^-7
The pH would be = -log [H+]
= -log[10^-7]
When inputted on a calculator this gives us 7
= 7
This is our answer
Answer:
You forget to compute the calculation systematically.
101.325 J/L*atm is obtained by dividing R in J/(mol*K) with R in L*atm/(mol*K)
Explanation:
Fo the given equation
Wrev = -nRtln(vf/vi)
We have the calculation below:
Wrev = -(1.000 mol)(0.08205 L*atm/mol*K)(298K)ln(10L/1L)
Wrev = -24.4509*ln(10) = -24.4509*2.303 = -56.3 L*atm
However, the unit was converted from L*atm to J by using a conversion unit derived from the ratio of gas constant (R) in J/(mol*K) and L*atm/(mol*K).
R = 0.082057 L*atm/(mol*K)
R = 8.3145 J/(mol*K)
Therefore, we can derive a conversion unit for L*atm to J as:
[8.3145 J/(mol*K)]/[0.082057 L*atm/(mol*K)] = 101.325 J/L*atm
Thus:
Wrev = -56.3 (L*atm) * 101.325 (J/L*atm) = -5705 J