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rusak2 [61]
3 years ago
15

Scintillatium has a halflife of 16 minutes. if a sample has 800 grams, find a formula for its mass after t minutes.

Chemistry
1 answer:
hichkok12 [17]3 years ago
8 0
<span>Halflife is the time needed for a radioactive molecule to decay half of its current mass. If t is the time elapsed, the formula for the halflife would be:
final mass= original mass * </span>\frac{1}{2} ^{\frac{t}{halflife}
<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass * \frac{1}{2} ^{\frac{t}{halflife}
final mass= 800g * \frac{1}{2} ^{\frac{t}{16 min}
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Sloan [31]
Mass and atoms are the properties conserved in every ordinary chemical reaction.

Hope this helps!
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3 years ago
Discuss the significance of assigning an atomic mass of exactly 12 amu to the carbon-12 isotope.
evablogger [386]

Answer:

Cabon-12 has same average atomic weight and mass number.

Explanation:

carbon-12 has average atomic weight 12 amu and mass number of 12.

amu represents average of mass of a nucleon.

As carbon-12 has same average atomic mass and mass number therefore carbon-12 is a good standard to determine average mass of a nucleon.

Again, abundance of carbon-12 isotope is almost equal to 99%. Therefore fluctuation of average atomic weight from 12 amu is very very low.

So, carbon-12 is taken as a standard to determine mass of a nucleon.

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5 0
3 years ago
Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi
erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon        7.3%          =     7.3g

hydrogen    4.5%         =      4.5g

oxygen       36.4%         =     36.4 g

nitrogen     31.8%         =     31.8 g

Now

For carbon

                    12 g --------------------1 mol

                    7.3 g     -------------     x

                       x = 7.3/12 = 0.608 mol

For hydrogen

                 1 g   --------------------  1 mol

                 4.5 g  ------------------    x

                   x = 4.5 mol

For oxygen

             16 g ------------------- 1 mol

             36.4 g ----------------    x

             x = 2.28 mol

For nitrogen

              14 g   ----------------   1 mol

              31.8 g ---------------    x

             x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon              0.608/0.608 = 1

hydrogen           4.5/ 0.608 = 7.4

oxygen              2.28/0.608 = 3.75

nitrogen             2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

     

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Answer:

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Explanation:

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