1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
2 years ago
5

Which bond is formed when a fatty acid is attached to a glycerol molecule? 2 of 8 QU

Chemistry
1 answer:
Mekhanik [1.2K]2 years ago
4 0

Answer: Heyo Kenji Here! Here's your answer- In a fat molecule, the fatty acids are attached to each of the three carbons of the glycerol molecule with an ester bond through the oxygen atom. During the ester bond formation, three molecules are released. Since fats consist of three fatty acids and a glycerol, they are also called triacylglycerols or triglycerides.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

You might be interested in
1. In an equilibrium experiment, acetic acid (which is a weak acid) is mixed with sodium acetate (a soluble salt), with methyl o
koban [17]

Explanation:

It is known that acetic acid is a weak acid. It's equilibrium of dissociation will be represented as follows.

          CH_{3}COOH(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COO^{-}(aq) + H_{3}O^{+}(aq)

On the other hand, sodium acetate (CH_{3}COONa) is a salt of weak acid, that is, CH_{3}COOH and strong base, that is, NaOH. Therefore, aqueous solution of sodium acetate will be basic in nature.

Since, acetic acid is a weak acid but still it is an acid. So, when methyl orange is added in a solution of acetic acid then it given a reddish-orange color because of its acidity.

When sodium acetate is mixed into this solution then it will dissociate as follows.

            CH_{3}COO^{-}Na^{+}(aq) \rightleftharpoons CH_{3}COO^{-}(aq) + Na^{+}(aq)

As both solutions are liberating acetate ion upon dissociation. Hence, it is the common ion.

So, when more acetate ions will increase from dissociation of sodium acetate the according to Le Chatelier's principle the equilibrium will shift on left side.

As a result, there will be decrease in the concentration of hydronium ions. As a result, there will be increase in the pH of the system.

Hence, color of methyl orange will change from reddish orange to yellow. This shift in equilibrium is due to the common ion which is CH_{3}COO^{-} ion.

4 0
3 years ago
Difference between dipole dipole and hydrogen bonding
riadik2000 [5.3K]

Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.

<h3>What is bonding in molecules?</h3>

Bonding is a type of attraction force which is present between the different atoms or elements of any substance.

  • Dipole dipole attraction force is a weak force as compared to the hydrogen bonding and present between any two oppositely charged atoms.
  • Hydrogen bond is present between the hydrogen atom and more electronegative atoms like O, S, N and F.

Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.

To know more about dipole-dipole force, visit the below link:
brainly.com/question/24197168

#SPJ4

8 0
2 years ago
Which is a symbol that represents SI units for temperature.
dsp73

Answer:

A.'C

Explanation:

Please answer my question

5 0
3 years ago
Read 2 more answers
The ___ of a bottle tells you how much liquid it can hold. what is the anewer
Sonbull [250]

Answer:

Volume

Explanation:

Volume is how much of a substance something can hold!

Hope this helped, have a nice day! :)

5 0
2 years ago
Read 2 more answers
The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A
Mamont248 [21]

Answer:

The  K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for B(g) = \frac{1}{2}A

            K_c=[B]^2[A]

                 = 0.045

The reverse will be 2B\leftrightharpoons A

Then,      K_c = \frac{[A]}{[B]^2}

                    =  \frac{1}{0.045}

                    = 22m^{-1}

The equilibrium constant for B(g) = \frac{1}{2}A will be

               K_c = \sqrt{K_c}

                    =\sqrt{22}

                    = 4.69

Therefore, K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

5 0
3 years ago
Other questions:
  • A delicate plant embryo is protected by what?
    13·2 answers
  • Match each career with the academic requirement for the job.
    7·2 answers
  • Naturally occurring iron contains:
    14·1 answer
  • Which statement about a system at equilibrium is true?(1) The forward reaction rate is less than the reverse reaction rate.(2) T
    11·2 answers
  • Which Domains would you find single cell organisms
    10·1 answer
  • Dan wants to test the effects of different amounts of antibiotic on bacteria. While setting up his experiment he makes sure to u
    12·1 answer
  • How many grams of CaCl2 are need to prepare 250 mL of a 0.15M solution?
    6·1 answer
  • Help me!!! :(<br> Plissss!!!!!
    11·1 answer
  • What transition energy corresponds to an absorption line at 460 nm?
    14·2 answers
  • The diameter of a circle is 17 cm. Find its circumference in terms of \piπ.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!