We can say that the water is the solvent, and the powder is the solute. This is also a solution altogether.
Explanation:- A solute is the thing being dissolved into the solvent. While the solvent is what when the solute is being dissolved in. Together, they make a solution.
Hydrophobic. Since bilayer has hydrophobic tail as their core region, molecules can pass through the hydrophobic tail if they are also hydrophobic.
To calculate the pH of this solution, we use the
Henderson-Hasselbalch equation:
pH = pKa + log ([A-]/[HA])
Where,
[A-] = Molarity of the conjugate base =
CH3COO- = 0.29 M<span>
<span>[HA] = Molarity of the weak acid = CH3COOH = 0.18 M</span></span>
pKa = dissociation constant of the weak acid =
4.75
When KOH is added to the buffer, the chemical
reaction is:
CH3COOH + KOH = CH3COO-K+ + H2O
Therefore when 0.0090 mol KOH is added, 0.0090
mol acid is neutralized, and 0.0090 mol CH3COO- is produced.
[CH3COO-] = [0.0090 mol + 0.375 L (0.29 mol/L) ]
/ 0.375 L = 0.314 M
[CH3COOH] = [-0.0090 mol + 0.375 L (0.18 mol/L) ]
/ 0.375 L = 0.156 M
Going back to Henderson-Hasselbalch
equation:
pH = 4.75 + log (0.314 / 0.156)
<span>pH = 5.054</span>
Answer:
0.164541341 g H2
Explanation:
1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).
2g Mg * (1 mol Mg / 24.31 g Mg) = 0.082270671 mol of Mg
2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.
0.082270671 mol of Mg = 0.082270671 mol of H2
3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).
0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2
* Answer can be rounded to your liking *
