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lora16 [44]
4 years ago
5

How do you know in a ionisation energy graph that sodium increases, magnesium increases and what elements decreases?​

Chemistry
1 answer:
FromTheMoon [43]4 years ago
4 0

Explanation:

Notice the spikes, it increases on the top and decreases at the bottom

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Need help plzz
Sveta_85 [38]

_____ are types of active transport.

(A)Diffusion and osmosis

<u>(B)Engulfing and transport proteins </u>

(C)Osmosis and engulfing

(D)Transport proteins and diffusion

5 0
3 years ago
At a given temperature, 3.12 atm of H2 and 5.52 atm of I2 are mixed and allowed to come to equilibrium. The equilibrium pressure
expeople1 [14]

Answer: 0.596

Explanation:

For this problem, we want to find K_{p}. To do so, we will need to use the ICE chart. The I in ICE is initial quantity. In this case, it is the initial pressure. Pressure is in atm. The C in ICE is change in each quantity. The E is equilibrium.

          H₂(g) + I₂(g) ⇄ 2HI(g)

I          3.12     5.52         0

C      -0.869  -0.869   +1.738

E       2.251    2.251     1.738

<u>For the steps below, refer to the ICE chart above.</u>

1. Since we were given the initial of H₂, I₂ and equilibrium of 2HI, we can fill those into the chart.

2. Since we were not given the initial for 2HI, we will put 0 in their place.

3. For the change, we need to add pressure to the products to make the reaction reach equilibrium. We would add on the products and subtract from the reactants to equalize the reaction. Since we don't know how much the change in, we can use variable x. We know that the equilibrium of 2HI is 1.738, we know the change is 0.869 because 1.738/2=0.869. Since there are 2 moles of HI, we must divide the equilibrium by 2 to find x, so that we can fill that into the reactants side.

4. With the equilibrium values, we can find the equilibrium pressure. It is products over reactants. We use the values of E.

K_{p} =\frac{[HI]^2}{[H_{2}][I_{2} ] }

The [HI]² comes from 2HI. We more the moles to the exponent when we are calculating the equilibrium pressure.

K_{p} =\frac{(1.738)^2}{(2.251)(2.251)} =0.596

We typically don't put units because K is unitless, but know that the units is atm throughout the entire problem.

5 0
3 years ago
Some please help please please someone
olganol [36]

The first one is force and the second is acceleration.

6 0
4 years ago
If 27mL of 6.0 M sulfuric acid was spilled, what is the minimum mass of sodium bicarbonate that must be added to the spill to ne
Law Incorporation [45]

Answer:- 27.2 g

Solution:- The balanced equation for the reaction of sulfuric acid with sodium bicarbonate is:

H_2SO_4+2NaHCO_3\rightarrow Na_2SO_4+2CO_2+2H_2O

From this equation, one mole of sulfuric acid reacts with two moles of sodium bicarbonate. We could calculate the moles of sulfuric acid from it's given volume and molarity. Then using mol ratio, we could calculate the moles of sodium bicarbonate required. Moles could easily be converted to grams on multiplying by molar mass.

The calculations would be shown as:

27mL(\frac{1L}{1000mL})(\frac{6.0moleH_2SO_4}{1L})(\frac{2moleNaHCO_3}{1moleH_2SO_4})(\frac{84gNaHCO_3}{1moleNaHCO_3})

= 27.2gNaHCO_3

So, 27.2 g of sodium bicarbonate are required to neutralize the given sulfuric acid solution.


5 0
3 years ago
calculate the enthalpy of formation for sulfur dioxide, s02, from its elements, sulfur and oxygen. Use the balanced chemical equ
sdas [7]

Answer:To check, it should be (−296.81±0.20) kJ/mol . You should use NIST more often. I actually got −310.17 kJ/mol though.

the balanced chemical equation stipulates the formation of two moles of sulfur trioxide when two moles of sulfur dioxide and one mole of oxygen react do now is determine how much heat is given off when one mole of sulfur.

8 0
4 years ago
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