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alisha [4.7K]
3 years ago
6

A plant was placed in the corner of a room away from a window. What might you observe about the plant after five days?

Chemistry
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

1. A. The plant leans toward window.

Explanation:

Plants need light to perform photosynthesis and live. Therefore, this means the plant will always lean toward light in order to survive.

- Hope that helps! Please let me know if you need further explanation.

Flura [38]3 years ago
8 0

Answer

Last one I think

Explanation:

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What is the molar concentration of hydronium ions in a sample of a soft drink that has a ph of 4?
hammer [34]

[H^{+}] value of soft drink is 0.0001mol/l when given pH is 4.

Given:

pH = 4

Needs to find: [H^{+}]

Formula to find: pH=−log_{10} [H^{+}]

We can put the values of pH in above formula as,

pH=−log_{10} [H^{+}]

4 =−log_{10} [H^{+}]

To calculate hydonium ion concentration, formula is as follows;

[H^{+}] = 10^{-pH}

[H^{+}] = 10^{-4} = 0.0001mol/l

[H^{+}] value of soft drink is 0.0001mol/l

Learn more about pH here:

brainly.com/question/2288405

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6 0
2 years ago
Which line represents a stationary object.
tiny-mole [99]

The green one cause its staying in the same position even when time is passing. - hope this helped have a great day

7 0
3 years ago
Read 2 more answers
If the E°cell value = +0.46V and E°(Ag+/Ag) = +0.80V
fenix001 [56]

Answer:

0.34

Explanation:

Cu>>>Cu2+(oxidation number increases)[Oxidation occurs]

Ag+>>>Ag(Oxidation number decreases) [Reduction occurs]

E°=0.80-0.46

=0.34V

8 0
2 years ago
Read 2 more answers
Which statement defines rate-determining step in a chemical reaction?
PilotLPTM [1.2K]
The correct response would be A. The slowest step that determines the speed(rate) of the overall reaction.
4 0
3 years ago
Read 2 more answers
A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con
inn [45]

Answer:

The equilibrium concentration of I₂ is 0.400 M  and HI is 1.20 M, the Keq will be 0.112.

Explanation:

Based on the given information, the equilibrium reaction will be,  

2HI (g) ⇔ H₂ (g) + I₂ (g)

It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,  

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.  

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.  

Now the equilibrium concentration of HI will be,  

= 2.00 -2x  

= 2.00 - 2 × 0.400

= 1.20 M

The equilibrium concentration of I₂ will be,  

I₂ = x  

= 0.400 M

The equilibrium constant (Keq) will be,  

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.  

5 0
3 years ago
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