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2 years ago

A normal probability distribution

Mathematics

1 answer:

julia-pushkina [17]2 years ago

6 0

Answer:

Option B) is a continuous probability distribution

Step-by-step explanation:

Properties of a normal probability distribution:

The mean, mode and median of the data is same.
It is a continuous probability distribution.
The area under the curve is 1.
The probability that any random variable X at a particular value is zero.

Thus, from the properties of normal distribution, the correct answer is:

Option B) is a continuous probability distribution

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State A and state B are among the states with the most remaining drive in movie screens. State A has 4 more screens than state B

mojhsa [17]

State A has 25 drive-in movie screens and State B has 21. You find this by guess-and-checking different numbers that you could add together to get 46. You want to do numbers that are relatively close, as a difference in 4 is not much at all. You can divide 46 by 2 and then play around from there.

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2 years ago

Given that these simultaneous equations

Tatiana [17]

The value of k is $(3\sqrt{ 10})/2$

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= $\sqrt{15-2x^2}$ ...........(eq iii)

Substitute the value of y into eq i

x-( $\sqrt{15-2x^2}$ = k

x- ( $\sqrt{15} - 2x$ = k

k= $(3\sqrt{ 10})/2$

Read more about simultaneous equations here:

brainly.com/question/16863577

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3 0

1 year ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0

1 year ago

Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6

Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

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3 years ago

Sarah drank 75% of a one-pint carton of milk at lunchtime. How many ounces of milk were left in the carton?

Ludmilka [50]

Answer:

Step-by-step explanation:

5 0

3 years ago