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netineya [11]
3 years ago
8

How is the concentration of H3O+ Ions is an OH-ions different and acid solution in a basic solution

Physics
1 answer:
mamaluj [8]3 years ago
8 0

Explanation:

In an acid solution, the concentration of H₃O⁺ ions is more than OH⁻

In a basic solution, the concentration of OH⁻ is more than that of H₃O⁺

By definition:

According to Arrhenius theory;

An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution. The hydroxonium ions formed as a result of the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its ionization.

A base is a substance that interacts with water to produce excess hydroxide ions, OH⁻ in an aqueous solution. The common bases are NaOH and KOH

learn more:

acid brainly.com/question/5121777

#learnwithBrainly

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Joe noted that the temperature in his aquarium dropped overnight. He concluded that thermal energy moved from the aquarium to th
alukav5142 [94]

Answer:

 validate                                            

Explanation:

<u>Law of Conservation of energy</u>

According to the law of conservation of energy, energy of a body or a system gets transferred to another system as different energy. We cannot create energy nor we can destroy energy. Energy is always transformed into other forms of energy.

In the context, Joe noticed that the aquarium's temperature dropped during the night and he concluded that according to the law of conservation of energy, the energy of the aquarium in terms of thermal energy is being transferred to the surrounding air.

This is because the aquarium is considered to be an open system where energy can come in and move out.

Hence Joe's statement is valid.

5 0
3 years ago
Read 2 more answers
How many moles of gas must be forced into a 4.6 l tire to give it a gauge pressure of 31.2 psi at 26 âc? the gauge pressure is r
Bess [88]
Use the Ideal Gas Law to the air in the tire : 

( P ) ( V ) = ( n ) ( R ) ( T ) 
n = ( P ) ( V ) / ( R ) ( T ) 
P = P gauge + P baro = 31.2 psig + 14.8 psia = 46 psia 
P = ( 46 psia ) ( 1 atm / 14.696 psia ) = 3.13 atm 
n = ( P ) ( V ) / ( R ) ( T ) 
n = ( 3.13 atm ) ( 4.6 L ) / ( 0.08206 atm - L / mol - K ) ( 26.0 + 273.2 K ) 
n = 0.5864 moles 
m = ( n ) ( M ) 
m = ( 0.5864 mol ) ( 28.96 g/ mol ) = 16.98 g
7 0
3 years ago
A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh
Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC  and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = \frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

3 0
3 years ago
What statement is true about the part of the electromagnetic spectrum that is visible to the human eye?
Alja [10]
Based on the options above, I see how the last option would actually be most fitting to how "the part of the electromagnetic spectrum that is visible to the human eye". This would be in separate parts, which would be divided into a certain number, which would actually be only 7 ranges of wavelengths. And therefore, this last statement would actually go very well and it would actually be the correct answer. And this would all relate to how <span> the part of the electromagnetic spectrum that is visible to the human eye, it's based on it's own 7 division parts that it has. 

Your answer: </span>\textsf{It is divided into seven ranges of wavelengths}
7 0
4 years ago
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A 23 kg suitcase is being pulled with a constant speed by a handle that is at an angle of 29° above the horizontal. If the norma
Zina [86]

<u>Answer:</u>

The force F applied to the handle = 330.03 N

<u>Explanation:</u>

    The force can be resolved in to two, horizontal component and vertical component. If θ is the angle between horizontal and applied force we have

     Horizontal component of force = F cos θ

    Vertical component of force = F sin θ

  In this problem normal force exerted on the suitcase is 160 N, that is  vertical component of force = 160 N and angle θ = 29⁰.

 So, F sin 29 = 160

        F = 330.03 N

 The force F applied to the handle = 330.03 N

6 0
3 years ago
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