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2 years ago

A child on a playground swing makes a complete to-and-fro swing each two seconds. The frequency of the swing is

1 answer:

4 0

Frequency=f
T=period of motion
f=1/T therefore f=1/2=0.500Hz or 0.5Hz

Hope this helps. Any questions please just ask. Thank you.

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A sample of water with a mass of 1 gram freezes at 32°F. At what temperature will a 100-gram sample of water freeze?

valkas [14]

Answer:

3200°F

Explanation:

just add two zero's to the end

8 0

3 years ago

A woman is standing in the ocean, and she notices that after a wavecrest passes, five more crests pass in a time of 50.0 s. Thed

Vadim26 [7]

Answer:

(a) T = 10 s

(b) f = 0.1 Hz

(d) v = 3.2 m/s

(e) Insufficient data

Explanation:

(a)

Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:

T = Period = Time Taken/No. of Waves

T = 50 s/5

T = 10 s

(b)

Frequency is the reciprocal of time period:

f = frequency = 1/T

f = 1/10 s

f = 0.1 Hz

(c)

Wavelength is the distance between two consecutive crests or troughs:

λ = Wavelength = 32 m

(d)

Speed of wave is given by the following formula:

Speed = v = fλ

v = (0.1 Hz)(32 m)

v = 3.2 m/s

(e)

Amplitude cannot be found with given data.

6 0

2 years ago

Use these options to describe each genotype

Sliva [168]

A homozygous dominant
B: homozygous recessive
C: heterozygous
I hope this helps you :)

4 0

3 years ago

Part complete Sound with frequency 1240 Hz leaves a room through a doorway with a width of 1.11 m . At what minimum angle relati

Sedbober [7]

Answer:

14.43° or 0.25184 rad

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 1240 Hz

d = Width in doorway = 1.11 m

Wavelength is given by

$\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343}{1240}\\\Rightarrow \lambda=0.2766\ m$

In the case of Fraunhofer diffraction we have the relation

$dsin\theta=\lambda\\\Rightarrow \theta=sin^{-1}\frac{\lambda}{d}\\\Rightarrow \theta=sin^{-1}\frac{0.2766}{1.11}\\\Rightarrow \theta=14.43^{\circ}\ or\ 0.25184\ rad$

The minimum angle relative to the center line perpendicular to the doorway will someone outside the room hear no sound is 14.43° or 0.25184 rad

6 0

2 years ago

A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it

Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

$F= ma (\rightarrow$ Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

$\rho = \frac{m}{V} \Rightarrow m = \rho V$

Part A) The buoyant force acting on the balloon is given as

$F_b = ma$

As mass is equal to the density and Volume and acceleration equal to Gravity constant

$F_b = \rho V g$

$F_b = 1.2*323*9.8$

$F_b = 3798.5$

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

$F_{net} = F_b -W$

$F_{net} = F_b -(mg+\rho_H Vg)$

$F_{net} = 3798.5-(9.8*225*9.8*0.179*323)$

$F_{net} = 1030N$

PART C) The additional mass that can the balloon support in equilibrium is given as

$F_{net} = m' g$

$m' =\frac{F_{net}}{g}$

$m' = \frac{1030}{9.8}$

$m' = 105Kg$

4 0

3 years ago