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3 years ago

How do you calculate centripetal acceleration?

1 answer:

8 0

A particle has centripetal acceleration whenever it's a making a turn of radius R. If the particle is moving at a constant tangential speed v throughout the turn, then the magnitude of centripetal acceleration is

v²/R

If the particle is following a uniformly circular path, then it moves in a circle of radius R and travels a distance equal to its circumference, 2πR. Let T be the time it takes to complete one such loop. Then the entire circle is traversed with speed v = 2πR/T, so that the centripetal acceleration is also given by

v²/R = (2πR/T)²/R = 4π²R/T²

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PLEASE HELP MEEE!! I WILL MARK YOU AS BRAINLIEST AND EVERYTHING!! THIS IS DUE TODAY AND MY GRADES ARE AT STAKE!:(

irina [24]

Answer:

They will be 140 miles apart 8 hours after the first boy started the trip or 6 hours after the second boy started the trip.

Explanation:

x = the time that the first boy travels at 14 mph

x - 2 = the time the second boy travels at 14 mph

140 the distance between them

Since one travels north and the other east (their roads are perpendicular) the distance between them can be calculated using Pythagorean Theorem

(14*x)^2 + ((x-2)*14)^2 = 140^2

the solutions of the quadratic equation are

x1 = - 6 is not the solution since x > 0

x2 = 8 h is the solution

3 0

3 years ago

Read 2 more answers

Jack tries to place magnets on the door of his refrigerator. He observes that the magnets don’t stick. He guesses that the door

ivanzaharov [21]

I think an education guess for this one because he is thinking about what to guess probably.

5 0

3 years ago

In a Young’s interference experiment, the two slits are separated by 0.150 mm and the incident light includes two wavelengths: l

dezoksy [38]

Answer:

2.52 × 10⁻² cm

Explanation:

The distance of bright fringe from the center of the screen is given by the formula

$y = \frac{m\lambda D}{d}$

Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the

slits is d.

Separation between the slits, d = 0.15 mm

$= 0.15 * 10^{-3} m$

Distance of the screen from the slits = 1.40 m

We have a wavelength, λ1 = 540 nm

= $540 * 10^{-9} m$

By substituting all these values in the above equation we get

y1 = mλD/d

$y1 = m(540 \times 10^{-9} m)(1.40 m)/(0.15 \times 10^{-3} m)$

$y1 = m(5.04 * 10^{-3} m)$

We have a wavelength, λ2 = 450 nm

= $450 * 10^-9 m$

By substituting all these values in the above equation we get

$y_2 = \frac{m\lambda D}{d}$

$y_2 = m(450 * 10^{-9} m)(1.40 m)/(0.15 * 10^{-3} m)$

$y_2 = m'(4.20 * 10^{-3} m)$

According to the problem, these two distance are coincides with each other.

So,

$y_1 = y_2$

$m(5.04 * 10^{-3} m) = m'(4.20 * 10^{-3} m)$

by testing values, the above equation is satisfied only when, m = 5 and m' = 6

Then from the above we have

y1 = y2 = 0.0252 m

= 2.52 × 10⁻² cm

8 0

3 years ago

A Michelson interferometer uses light with a wavelength of 452.446 nm. Mirror M2 is slowly moved a distance x, causing exactly 2

I am Lyosha [343]

Answer:

Option b. Dark spot

Explanation:

Michelson interferometer gives the path difference of the light as path difference, d as twice the distance moved or covered by the mirror $M_{2}$ , x and is given as:

d= 2x

Since, its an even multiple, we obtain a bright fringe

now, when the move half the distance, i.e., $\frac{x}{2}$

Therefore, the path difference for half the distance $\frac{x}{2}$ is:

d = x

As it is clear that its an odd multiple which correspond to dark spot as the final image

3 0

4 years ago

"A parcel moving in a horizontal direction with speed v0 = 13 m/s breaks into two fragments of weights 1.4 N and 1.9 N, respecti

Lady bird [3.3K]

Answer:

the smaller particle moves with speed of 8.706 m/s in the opposite direction to the bigger particle.

Explanation:

Speed of the original particle = 13 m/s

We designate particles as A and B

The final weights of the component particles are

Particle A = 1.4 N

particle B = 1.9 N

The speed of the larger piece (particle B) = 29 m/s

We know that weight is the product of a body's mass and acceleration due to gravity g which is equal to 9.81 m/s^2, therefore, masses of the particles are

particle A = 1.4/9.81 = 0.143 kg

Particle B = 1.9/9.81 = 0.194 kg

The momentum of a body is the product of its mass and its velocity i.e

P = mv

This means that the mass of the particle before splitting is

0.143 kg + 0.194 kg = 0.337 kg

Momentum of the initial whole particle = mv

==> 0.337 x 13 = 4.381 kg-m/s

The bigger particle B remains horizontal, and has a momentum of

mv = 0.194 x 29 = 5.626 kg-m/s

According to the conservation of momentum, the total initial momentum of a system must be equal tot the total final momentum of the system.

Initial total momentum of the system = 4.381 kg-m/s (momentum of original particle before splitting)

Final total momentum of the system = Total momentum of the particles after splitting = 5.626 kg-m/s + ( 0.143 kg x $V_{B}$ )

where $V_{B}$ is the velocity of smaller particle A

final total momentum of the system = 5.626 + 0.143 $V_{B}$

Equating the two momenta of the system, we'll have

4.381 = 5.626 + 0.143 $V_{B}$

4.381 - 5.626 = 0.143 $V_{B}$

-1.245 = 0.143 $V_{B}$

$V_{B}$ = -1.245/0.143 = -8.706 m/s

The negative sign indicates that the smaller particle moves in the opposite direction to the bigger particle

5 0

3 years ago