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Lilit [14]
2 years ago
13

Triangle+ Triangle + Triangle = 30 Triangle + circle + circle = 20 Circle + Square + Square = 13 Triangle + circle x half square

= ?
Answers = 30, 25, 15 or 20
Mathematics
1 answer:
Rasek [7]2 years ago
4 0
Answer: 20
Explanation: triangle=10 , circle= 5 , square= 4 , half square = 2....... 5 x 2 = 10 plus 10 = 20:)
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Simplify the expression in e^5
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Step-by-step explanation:

ok im not sure if this is it but 148.41315910

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Suppose the function f(t) = 95 cosine (StartFraction pi Over 10 EndFraction t) + 120 models the height of a seat on a Ferris whe
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im not 100% bit i think its 95ft

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For her college fund jenny's parents invested $5000 four years ago. the account has now reached $6312. what is the approximate a
Tasya [4]

Answer:

Rate = 6.56%

Step-by-step explanation:

Principal (P) = $5000

Interest (I) = $6312

Time (T) = 4 years

Rate (r) = ?

This question is involves simple interest and with the formula, we can easily plug in the values to find the rate.

S.I = P(1 + rt)

S.I = simple interest

P = principal

R = Rate

T = Time

6312 = 5000(1 + r*4)

6312 = 5000 + 5000*4r

6312 - 5000 = 20000r

1312 = 20000r

r = 1312 / 20000

r = 0.0656

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4 0
3 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

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Brilliant_brown [7]
The speed is 4 meters per second
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