Answer:
N2
Explanation:
Rate of effusion is defined by Graham's Law:
(Rate 1/Rate 2) = (sqrt (M2)/ sqrt (M1))
(Where M is the molar mass of each substance. )
Molar Mass of oxygen, O2, is 32 (M1).
Rate of effusion of O2 to an unknown gas is .935(Rate 1).
Rate 2 is unknown so put 1.
Solve for x (M2).
.935/1 = sqrt x/ sqrt32
.935 x sqrt 32 = sqrt x
5.29 = sq rt x
5.29^2 = 27.975 = 28
N2 has a molar mass of 28 so it is the correct gas.
Mitosis is conventionally divided into 5 phases, which include prophase, prometaphase, metaphase, anaphase and telophase and cytokinesis.
Interphase
Before coming into mitosis, a mobile spends a length of its increase underneath interphase.
Prophase
Prophase straight away follows the S and G2 levels of the cycle and is marked by way of condensation of the genetic fabric to form compact mitotic chromosomes composed of chromatids attached at the centromere.
Prometaphase
In the prometaphase, the nuclear envelop disintegrates. Now the microtubules are allowed to extend from the centromere to the chromosome.
Metaphase
At this level, the microtubules start pulling the chromosomes with equal pressure and the chromosome ends up in the center of the cell. This area is referred to as the metaphase plate.
Anaphase
The splitting of the sister chromatids marks the onset of anaphase. These sister chromatids end up the chromosome of the daughter nuclei.
Telophase
The chromosomes that cluster at the two poles start coalescing into an undifferentiated mass, because the nuclear envelope begins forming round it.
To know more about mitosis at
brainly.com/question/8757261
Hey there!
Great question;)
Answer:It is neutrally charged, because it has the same number of electrons(negatively charged ions) and protons(positively charged ions)
I hope this helps;)
Answer:
Oxygen is not released into the atmosphere
-The marine sediments are formed into rocks by Earth's geologic processes
Answer:
6.75 moles of CuCl₂ were used
Explanation:
Given data:
Number of moles of AlCl₃ formed = 4.5 mol
Number of moles of CuCl₂ used = ?
Solution:
Chemical equation:
3CuCl₂ + 2Al → 2AlCl₃ + 3Cu
Now we will compare the moles of CuCl₂ and AlCl₃
AlCl₃ : CuCl₂
2 : 3
4.5 : 3/2×4.5 = 6.75
6.75 moles of CuCl₂ were used.
