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3 years ago

A solution is 12.5% Na3PO, by mass. How many grams of Na3PO4

Chemistry

1 answer:

Harman [31]3 years ago

7 0

<h2>Answer: 4.94 g </h2>

Explanation:

Mass of solution of Na₃PO₄ = volume × density

= 35.9 mL × 1.10 g/mL

= 39.49 g

Now, since the solution only contains 12.5% Na₃PO₄, then the mass of Na₃PO₄ is 12.5% of 39.49 g

12.5% × 39.49 g = 4.94 g

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If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Mamont248 [21]

Answer:

17.3 g

Explanation:

Given the following data;

Quantity of heat, Q = 0.507 J
Temperature = 0.007°C
Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

$Q = MCT$

Where;

Q represents the heat capacity or quantity of heat.
M represents the mass of an object.
C represents the specific heat capacity of water.
T represents the temperature.

Making "M" the subject of formula, we have;

$M = \frac {Q}{CT}$

Substituting the values into the formula, we have;

$M = \frac {0.507}{4.2*0.007}$

$M = \frac {0.507}{0.0294}$

Mass, m = 17.3 grams

8 0

2 years ago

14. pH value are basic are greater than what number while acids are have a pH less than

Mice21 [21]

Answer:

Less than 7 ph value are acidic. Greater than 7 ph value are basic.

5 0

3 years ago

Aluminum has a density of 2.70 g/cm3. what would be the mass of a sample whose volume is 10.0 cm3?

anastassius [24]

Hey there!

Density = 2.70 g/cm³

Volume = 10.0 cm³

Therefore:

Mass = density * volume

Mass = 2.70 * 10.0

Mass = 27.0 g

3 0

3 years ago

PLEASE HELP IM SO CONFUSED How does potassium need to be modified either on site or in a factory to make it useful. This should

3241004551 [841]

Potassium is not found free in nature but is found in the form of potash. Potash is the ore of potassium and this ore is mined from deep down the earth or can sometimes be found on the surface. Potash was mostly formed as sea water receded and left deposits.

Potash is usually in the form of potassium salts such potassium chloride and potassium sulphate. The potash is mined then taken to the factory where it is crushed and purified by removing such impurities as clay.

The now purified potassium salts are subjected to a process called electrolysis where potassium metal is obtained from its salt.

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3 years ago

A gaseous compound is 30.4 % N and 69.6% OF. A 5.25 g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 958

Harman [31]

Answer:

The molecular formula = N2O4

Explanation:

Step 1: Data given

A gaseous compound is 30.4 % N and 69.6%

Mass of the compound = 5.25 grams

Volume of the gas = 1.00 L

Pressure of the gas = 958 mmHg = 1.26 atm

Temperature of the gas = -4 °C = 273 -4°C = 269 Kelvin

Molar mass of N = 14 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate mass of N

Mass of Nitrogen = 5.25 grams * 0.304 = 1.596 grams

Step 3: Calculate mass of O

Mass of Oxygen = 5.25 grams * 0.696 = 3.654 grams

Step 4: Calculate number of moles N

Number of moles N = Mass of N/ Molar mass of N

Moles of N = 1.596 grams / 14g/mol

Moles of N = 0.114 moles N

Step 5: Calculate moles of O

Moles O = 3.654 grams / 16 g/mol

Moles 0 = 0.2884 moles

Step 6: Calculate empirical formule

We calculate the empirical formule by dividing number of moles by the smallest number of mol

N : 0.114 / 0.114 = 1

O: 0.2284 / 0.114 = 2

Empirical formule = NO2

Step 7: Calculate number of moles of 5.25 g sample via gas law:

p*V = nRT

⇒ with p = the pressure = 1.26 atm

⇒ with v = 1.00 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/ K*mol

⇒ with T = the temperature = 269 K

number of moles n = (p*V)/(R*T)

n = (1.26*1L)/(0.08206*269)

n = 0.057 mol

Step 8: Calculate molar mass of the compound

This means 5.25 grams of the gas = 0.057 moles

So 1 mol of the compound has a molar mass of: 5.25 / 0.057 = 92.11 g/mol

Step 9: Calculate molar mass of the empirical formula NO2

N = 14 g/mol

O = 16 g/mol

NO2 = 14 + 16 + 16 = 46 g/mol

The empirical formule NO2 has a molar mass of 46 g/mol

Step 10: Calculate molecular formula

92.11 / 46 = 2

This means the empirical formula should be multiplied by 2

2*(NO2) = N2O4

The molecular formula = N2O4

8 0

3 years ago