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True [87]
2 years ago
12

A solution is 12.5% Na3PO, by mass. How many grams of Na3PO4

Chemistry
1 answer:
Harman [31]2 years ago
7 0
<h2>Answer:  4.94 g   </h2>

Explanation:

Mass of solution of Na₃PO₄ = volume  × density

                                              =   35.9 mL × 1.10 g/mL

                                              =   39.49 g

Now, since the solution only contains 12.5% Na₃PO₄, then the mass of Na₃PO₄ is 12.5% of 39.49 g

                                 12.5% × 39.49 g = <u>4.94 g   </u>        

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Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

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\pi=icRT

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\pi = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

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Putting values in above equation, we get:

0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L

The concentration of solute is 2.4278\times 10^{-5} mol/L

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Moles of β‑Galactosidase = n

C=\frac{n}{V(L)}

n=2.4278\times 10^{-5} mol/L\times 0.137 L

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol

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3 0
2 years ago
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The molar mass of M is  0.225g/mol and the element M is Hydrogen

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Given the following parameters

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