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Dimas [21]
3 years ago
15

What factor can limit the buffering capacity of a molecule?

Chemistry
1 answer:
Bad White [126]3 years ago
8 0

Answer:

The concentration and pKa of an acid and its conjugate base can limit the buffering capacity of a molecule.

Explanation:

A buffer is an acid and its conjugate base and the quality of it depends on its buffer capacity. This buffer capacity is the resistance to change the pH of the solution when strong acids or bases are added. The buffer capacity is related to the buffer concentration, the concentration of the acid end its conjugate base. Also, every acid has a pKa and the buffer capacity is at its maximum at the pKa value and can buffer the solution between ± 1 the pKa value.

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Which statement about the self-ionization of water is correct?
ASHA 777 [7]

Answer: Two water molecules interact to form a hydronium ion and a hydroxide ion.

Explanation:

5 0
3 years ago
Rank the speeds of sound through these materials, from greatest to least:a. Airb. Steelc. Water
s344n2d4d5 [400]

Ranking order of speed of sound is; Steel >Water > Air.

Speed of sound in normal air is 340 m/s, in water the speed is 1,430 m/s and in steel the speed is 5920 m/s.

<h3>What is speed of sound?</h3>

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learn more about speed of sound: brainly.com/question/20319989

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7 0
1 year ago
the element weighed 3.555 grams when it was burned in oxygen an oxide compound was produced. the product mass was 4.666 grams. W
vodka [1.7K]
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6 0
3 years ago
MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent
Katen [24]
HCl:
<span>
m=48,2g
M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol          : 4mol
MnO</span>₂        + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol     :  1,32mol
                     limiting reagent 
0,33 will react

HCl is limiting reagent.
6 0
3 years ago
A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the fi
joja [24]

Answer:

474.64mmHg

Explanation:

From the question given, we obtained the following:

V1 = 10L

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P1V1 = P2V2

10 x 655 = P2 x 13.8

Divide both side by the coefficient P2 i.e 13.8

P2 = (10 x 655) / 13.8

P2 = 474.64mmHg

Therefore, the new pressure will be 474.64mmHg

7 0
3 years ago
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