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marta [7]
3 years ago
14

Calculate how many molecules are present in the following quantities.

Chemistry
2 answers:
Montano1993 [528]3 years ago
8 0
H20 = 2.741 x 10^23
C6H8 = 1.0823 x 10^23
KATRIN_1 [288]3 years ago
4 0
Hope this helps, have a great day ahead!

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250 mL of a solution of calcium oxalate is the evaporated until only a residue of solid calcium
Lana71 [14]

Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

Ksp = 2.3 * 10^-5

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What are essential and non essential proteins ?
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<span>0.002 moles is the answer </span>
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Physical properties can be used to describe matter. Some properties are dependent on the amount of matter present. All BUT ONE o
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What the requirement for a reversible reaction to be at equilibrium ?
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