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3 years ago

6

Which intermolecular forces increase rapidly with increasing molecular size?

1 answer:

blondinia [14]3 years ago

8 0

LONDON DISPERSION FORCES

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Match the condensed structural diagrams with the correct names

AleksAgata [21]

Answer:

Here's what I get

Explanation:

1. Names

I. CH₃-CH₂-COOH = 49. propanoic acid

II. CH₃-CH₂-OH = 46. ethanol

III. CH₃-COO-CH₂-CH₂-CH₃ = 47. propyl ethanoate

IV. H-O-CH₂-CH₂-CH₃ = 48. propan-1-ol

V. H-COO-CH₃ = 51. methyl methanoate

VI. CH₃-COOH = 50. ethanoic acid

2. Precursors

52. methyl propionate ⇒ methanol + propanoic acid

53. ethyl methanoate ⇒ ethanol + methanoic acid

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3 years ago

If two elements are from the

Vladimir79 [104]

Answer:

The element from Group 13.

Explanation:

Following trends of the periodic table, atomic radius of the elements increase going down from the right side and decrease on its way up diagonally to the left. (sry if u can't understand me)

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3 years ago

What definition BEST describes a watershed?<br> Please help please!!!!

Nadusha1986 [10]

Answer:

it is b

Explanation:

A drainage basin is any area of land where precipitation collects and drains off into a common outlet, such as into a river, bay, or other body of water

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2 years ago

What is the heaviest gas element

Katen [24]

Here it is. Radon is the heaviest gas element

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3 years ago

Read 2 more answers

Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A

dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

$2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)$

$3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)$

Firstly, find the total number of moles of magnesium metal:

$n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol$

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

$x + y = 0.041144 mol$

According to stoichiometry, we form:

$n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol$

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

$m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =$

The total mass is given, so we have our second equation to solve:

$40.31x + 33.65y = 1.584$

We have two unknowns and two equations, we may then solve:

$x + y = 0.041144$

$40.31x + 33.65y = 1.584$

Express y from the first equation:

$y = 0.041144 - x$

Substitute into the second equation:

$40.31x + 33.65(0.04144 - x) = 1.584$

$40.31x + 1.39446 - 33.65x = 1.584$

$6.66x = 0.18954$

$x = 0.028459$

$y = 0.041144 - x = 0.012685$

Moles of nitride formed:

$n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol$

Convert this to mass:

$m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g$

Find the percentage:

$\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%$

7 0

2 years ago