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lianna [129]
3 years ago
10

The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is​

Chemistry
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

Hope this Helps (✿◡‿◡)

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Nitrogen ​gas is more abundant in our atmosphere than oxygen! However, nitrogen needs to be converted into different forms to be
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Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH=1.06×10
kkurt [141]

Answer:

The diameter of the hydrogen \mathbf{d =1.0605 \times 10^{-10}\ m}

Explanation:

From the given information:

Using the concept of Bohr's Model, the equation for the angular momentum can be expressed as:

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replacing the value of L into the previous equation, we have:

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The electron in the hydrogen atom posses an electrostatic force which gives a centripetal force.

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replacing the value of v in equation (1) into (2), and taking r as the subject of the formula, we have:

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r =\dfrac{n^2h^2}{4 \pi^2 mke^2}

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h = (6.625 \times 10^{-34} \ J.s)^2

m =( 9.1 \times 10^{-31} \ kg)(9 \times 10^9 \ N .m^2/C^2)

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r =\dfrac{(1)^2(6.625 \times 10^{-34})^2}{4 \pi^2 (9.1 \times 10^{-31} )(9 \times 10^9 ) (1.6 \times 10^{-19})^2}

r =\dfrac{4.3890625 \times 10^{-67}}{8.27720295 \times 10^{-57}}

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\mathbf{d = ( 2 \times  5.3025 \times 10^{-11} \ m})}

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