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Vedmedyk [2.9K]
3 years ago
9

Solve this linear system using determinants: 2x + 3y = 6 −8x − 3y = 12

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0

Answer:

|A| =  18

|Ax| =  -54

|Ay| =  72

x =  -3

y =  4

strojnjashka [21]3 years ago
3 0

\left\{\begin{array}{ccc}2x+3y=6\\-8x-3y=12\end{array}\right\\\\A=\left[\begin{array}{ccc}2&3\\-8&-3\end{array}\right] \\\\|A|=\left|\begin{array}{ccc}2&3\\-8&-3\end{array}\right|=(2)(-3)-(-8)(3)=-6+24=18\\\\|A_x|=\left|\begin{array}{ccc}6&3\\12&-3\end{array}\right|=(6)(-3)-(12)(3)=-18-36=-54\\\\|A_y|=\left|\begin{array}{ccc}2&6\\-8&12\end{array}\right|=(2)(12)-(-8)(6)=24+48=72\\\\x=\dfrac{|A_x|}{|A|}=\dfrac{-54}{18}=-3\\\\y=\dfrac{|A_y|}{|A|}=\dfrac{72}{18}=4\\\\Answer:\ x=4,\ y=-3

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MrRa [10]
The above equation is invalid. It is not equal.

-10 = -14v + 14v

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-10 = 0  This is not equal. There is no solution. Thus, the equation is invalid.


3 0
3 years ago
50 points
Artemon [7]

Answer:

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Step-by-step explanation:

i) area of circle = \pi \times r^{2}  = 9\pi \hspace{0.1cm} where \hspace{0.1cm}r = 3.

ii) therefore side of hexagon, a = 2\sqrt{3}

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iv) difference between the two areas in iii) and i)  =9(2\sqrt{3} -\pi)

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motikmotik

Answer:

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Step-by-step explanation:

(Could be wrong, I'm just browsing through brainly and thought it looked easy)

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