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3 years ago

A(n) _____ is a testable statement about a relationship between two variables.

Mathematics

1 answer:

Monica [59]3 years ago

6 0

Answer:

d. hypothesis

Step-by-step explanation:

According to all the scientific studies that are created or developed every day, Scientists call what is described in the question a "hypothesis". This is defined as a proposed explanation for a specific phenomenon. The hypothesis is the base for creating a testable experiment that proves the relationship between two variables.

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Points B, D, and F are midpoints of the sides of ΔACE.

Ainat [17]

Answer:

Step-by-step explanation:

D to c = 15, DtoB =17 so Cto B= 17

and A to C =34

8 0

3 years ago

A line is represented by the equation 2x + 3y = 15. What is another way to represent the same line, for solving Y ? Help is need

Lady bird [3.3K]

The another way to represent the same line, for solving $y$ will be: $y= 5-\frac{2}{3}x$

Explanation

Given equation of the line is: $2x+3y=15$

"Solving $y$ " means we need to get $y$ alone in left side. So, we will eliminate all other terms except $y$ from the left side.

First we will subtract 2x from both sides. So, we will get......

$2x+3y-2x=15-2x\\ \\ 3y=15-2x$

Now, we will divide both sides by 3 for getting $y$ alone. So.....

$\frac{3y}{3}= \frac{15-2x}{3}\\ \\ y= 5-\frac{2}{3}x$

Thus, the another way to represent the same line, for solving $y$ will be: $y= 5-\frac{2}{3}x$

7 0

4 years ago

The operation * on the set Z of integers is defined by x*y = 3x + 2y - 1, x, y E Z. Find the value of x such that x*2=5

Assoli18 [71]

Answer:

x = 2/3

Step-by-step explanation:

Let's unpack the equation $x*2=5$ from our definition of $*$ :

$x*2=3x+2(2)-1=5$ (where $x\in \mathbb{Z}$ )

Now that we've got things defined in terms of familiar operations, we can simplify and solve for x:

$3x+2(2)-1=5\\3x+4-1=5\\3x+3=5\\3x=2\\x=2/3$

8 0

3 years ago

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

3 years ago

Employment Frequency

Citrus2011 [14]

Answer:

my appleas arw yellow

Step-by-step explanation:

5 0

2 years ago