The pressure of the gas <u>would increase.</u>
Explanation:
Using the ideal gas formulae we can evaluate this fact;
P₁V₁/T₁ = P₂V₂/T₂
We can assume that the volume is reduced by half (the T₁ and T₂ will cancel out because they remain constant);
P₁V₁ = P₂ * 0.5V₁
P₁V₁/0.5V₁ = P₂
P₁/0.5 = P₂
You can observe that the pressure will also increase – diving a number by a fraction or decimal number increases the resultant value. In this case, the pressure will increase by 2 fold
The formula they can use is Length multiplied by Width Multiplied by Height
Answer:
large atoms have Valence electrons further from the nucleus and lose them more readily.
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ - (1)
where, t1/2 is half-life and λ is the decay constant.
Nt = Nοe∧(-λt) - (2)
Nt = amount of atoms at t =t time
Nο = initial amount of atom
t = time taken
From (1),
10 yr = 0.693 / λ
λ = 0.693 / 10 yr
From (2)
Nt = 100 g eΛ(-(0.693 / 10 yr) x 20 yr)
Nt = 25.00 g.
Hence, remaining mass will be 25.00 g
A is the answer to this question