Answer:
CH2O and C6H12O6
Explanation:
To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.
Annually 126.0 million metric tons of soil nutrients are lost.
<u>Explanation</u>:
- By the given data we can identify the loss of soil nutrients in the United States. In the first year, a total of 1.0 million soil nutrients are lost.
- After that in the second year, the loss has doubled. 10.0 million metric tons of soil nutrients are lost.
- In the third year, 16.0 million soil nutrients are lost in the US.
- In the final year, 90.0 million soil nutrients are lost. It is a very huge loss. By calculating all the above , a total 126.0 million of soil nutrients in the US are lost annually.
The computation for molarity is:
(x) (0.175 L) = 0.0358 g / 598 g/mol
x = 0.000342093 M
Whereas the osmotic pressure calculation:
pi = iMRT
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K)
pi = 0.0083655 atm
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr
which rounds off to 6.36 torr
Answer:
Structure in attachment.
Explanation:
The oxymercuration-demercuration of an asymmetric alkene usually produces the Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two carbon atoms, but there is more positive charge on the more substituted carbon atom, where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.
In hydroboration, borane adds to the double bond in one step. Boron is added to the less hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.
Your answer would be GLYCERALDEHYDE.
Hope that helps!!!!
