What is the final temperature of the metal

Mademuasel [1]

With a name like poly hydroxyl alcohol, it suggests that the alcohol has more than one alcohol group. Thus any alcohol with more than one hydroxyl is a polyhydroxyl alcohol. An example that pops into mind is ethanediol (CH2OHCH2OH) this has 2 hydroxyl groups and is an alcohol, thus a polyhydroxyl alcohol

8 0

3 years ago

If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?

Mazyrski [523]

Silicon is the element having a mass of 28.09 g

Explanation:

Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 $\times$ 10^23 atoms. One mole of each element can produce one mole of compound.

The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 $\times$ 10^23).

Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 $\times$ 10^23 atoms of an element are equal to the average atomic mass of that element.

8 0

3 years ago

How to balance NH3+NO=N2+H2O

Kryger [21]

Explanation:

NH₃+NO=N₂+H₂O;

NH₃+NO=N₂+6H₂O;

NH₃+6NO=N₂+6H₂O;

4NH₃+6NO=N₂+6H₂O;

4NH₃+6NO=5N₂+6H₂O.

3 0

1 year ago

If you were given two transparent liquids how would you determine which is pure and which is salt water

Tpy6a [65]

Based off the salt levels in each water.

8 0

3 years ago

Problem PageQuestionSteam reforming of methane ( ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas,

Serhud [2]

The question is incomplete. Her eis the complete question.

Steam reforming methane (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

Answer: $K_{c}$ = 2. $10^{-2}$

Explanation: The reaction for steam reforming methane is:

$CH_{4} + H_{2}O$ ⇒ $CO_{} + 3H_{2}$

To calculate the concentration equilibrium constant, first calculate the molarity ( $\frac{mol}{L}$ ) of each molecule of the reaction.

At 38°C: At the initial temperature, there no products yet

Molarity of CH4:

CH4 = $\frac{20}{125}$ = 0.16M

Molarity of H20:

H2O = $\frac{10}{125}$ = 0.08M

At final temperature:

Molarity of H2:

H2 = $\frac{18}{125}$ = 0.144M

According to the chemical reaction, the combination of 1 mol of each reagents produces 1 mol of CO and 3 mols of H2, so, for the products, the ratio is 1:3.

Molarity of CO:

CO = $\frac{0.144}{3}$ = 0.048M

For the reagents, the proportion is 1:1, but they had an initial concentration, so, when in equilibrium, the concentration will be:

Molarity of CH4:

CH4 = 0.16 - 0.048 = 0.112M

Molarity of H2O:

H20 = 0.08 - 0.048 = 0.032M

The equilibrium constant is given by:

$K_{c} = \frac{[CO][H_{2}]^{3} }{[CH_{4}][H_{2}O ] }$

$K_{c}$ = $\frac{0.048.0.144^{3} }{0.112.0.032}$

$K_{c}$ = 2. $10^{-2}$

The concentration equilibrium constant for the process is $K_{c}$ = 2. $10^{-2}$ .

4 0

3 years ago

What is the final temperature of the metal​

What is the final temperature of the metal