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Zolol [24]
3 years ago
15

Why does an atom of 23NA have 23 electrons

Chemistry
1 answer:
Julli [10]3 years ago
7 0
It is actually something standardized more so than theoretical,  however in terms of atoms in general the electrons are based on the amount of  electronic shells that an atom has and the amount of electrons that atom can accommodate.  In the case of sodium, it has three shells with 2 electrons on the first shell which is the maximum, 8 on the second shell which is also the max and 1 on their final shell
So simply put an ATOM of Sodium (Na) has 23 electrons because it has 23 protons which is a fact
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How does an indicator differentiate between an acid and base?
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Calculate the heat energy required to melt 4kg of ice when the specific latent heat of fusion of water is 334,000 J/kg.
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Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat energy required to melt ice</h3>

In this case, you know:

  • m= 4 kg
  • L= specific latent heat of fusion of water= 334,000 \frac{J}{kg}

Replacing in the expression for latent heat:

Q = 4 kg× 334,000 \frac{J}{kg}

Solving:

<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)

Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

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