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serg [7]
3 years ago
11

What is the mass (in grams) of 8.45 x 1023 molecules of dextrose: C6H12O6 (Mw. 180.16 g/mol)?

Chemistry
1 answer:
Goryan [66]3 years ago
4 0
<span>The mass (in grams) of 8.45 x 10^23 molecules of dextrose is 252.798g Working: Mw. dextrose is 180.16 g/mol therefore 180.16 grams dextrose = 1 mole therefore 180.16 grams dextrose= 6.022x10^23 molecules (Avogadro's number) We have 8.45 x 10^23 molecules of dextrose. Therefore, (180.16 divided by 6.022x10^23) times 8.45x10^23 gives the mass (in grams) of 8.45 x 10^23 molecules of dextrose; 252.798.</span>
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Greg’s table is incorrect because sand is insoluble in water.

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • N₂: 1 mole
  • H₂: 3 moles
  • NH₃: 2 moles

The molar mass of the compounds is:

  • N₂: 14 g/mole
  • H₂: 2 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×14 g/mole= 14 grams
  • H₂: 3 moles ×2 g/mole= 6 grams
  • NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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2 years ago
If a material conducts heat easily, its a good _____. <br> It has to be a 18 letter word
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Answer:

a thermal conductor

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7 0
3 years ago
8.5ml of a sample of sea water solution was added to a 44.317g evaporating dish the combination weighted 52.987g after evaporati
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Answer:  There is no question, but we can calculate a couple of items:

Density of sea water sample = (52.987g-44.317g)/8.5ml

Inorganic content of sample (mostly salts) = (44.599g-44.317g)/(52.987g-44.317g) x 100% = percent inorganics in water sample

Explanation:

5 0
3 years ago
An ideal gas in a 1.25-gallon container is at a temperature of 125 degrees Celsius and pressure of 2.5 atmospheres. If the gas i
Tresset [83]
You will need the equation PV = nRT

P = Pressure in kPa
V = Volume in L
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R = 8.314 (constant)
T = Temperature in Kelvin 

First convert 2.5 atm into kPa:

2.5 X 101.3 = 253.25 kPa

Convert 125 Celsius into Kelvin:

125 + 273 = 398 K

Convert Gallons to Litres:

1.25  X 3.79 = 4.74 L

Plug your values into the equation to solve for n:

(253.25)(4.74) = n(8.314)(398)

n = (253.25)(4.74)/(8.314)(398)

n = 0.362 moles

Now use M = m/n to solve for the mass of O2

M = Molar Mass 
M = mass
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32 = m/(0.362)

m = (32)(0.362) 

m = 11.58g
8 0
3 years ago
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