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sweet [91]
3 years ago
12

Elements on the periodic table are organized by what?

Chemistry
2 answers:
Sever21 [200]3 years ago
8 0
Increasing atomic mass
kogti [31]3 years ago
4 0

increasing atomic number

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When CO2 decomposes into oxygen and carbon, it gives a gram ratio of 2.67:1 O2:C. When a 32.4g of CO2 decomposes, how many grams
Rufina [12.5K]

Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

CO_2\rightarrow O_2+C

As we are given:

\text{Mass of }O_2}:\text{Mass of }C=2.67:1{

According to the law of conservation of mass,

Total mass of CO_2 = Mass of O_2 + Mass of C

Total mass of CO_2 = 2.67 + 1 = 3.67 g

Now we have to calculate the mass of O_2 and C.

\text{Mass of }O_2=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }O_2=\frac{32.4g}{3.67g}\times 2.67=23.6g

and,

\text{Mass of }C=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }C=\frac{32.4g}{3.67g}\times 1=8.83g

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

6 0
3 years ago
Hi! My responsibility is to add and protection to plant cells. what i am​
liq [111]
Probably a cell wall
4 0
3 years ago
Why does LiCl does not exhibit frenkel defect?
tino4ka555 [31]
Frenkel defect is a defect in crystalline solids in which an atom is displaced from its lattice position to an interstitial space. This creates a vacant space at the original site and an  interstitial defect at the new site within the same element. This defect does not affect the chemical properties of the compound. This defect usually occur in ionic solids with large size difference between the anion and cation.
LiCl does not exhibit Frenkel defect because the size difference between the anion and the cation of the compound is very small.
3 0
3 years ago
A student prepares two solutions as shown. The dots represent solute particles. The student wants to test the conductivity of ea
stealth61 [152]

Answer:

I think its D

Explanation:

It cant be B or C bc the solute particles arent changing. And  its not A because the concentration isnt constant

3 0
2 years ago
Write balanced chemical equation for the reactions used to prepare each of the following compounds from the given starting mater
creativ13 [48]

Explanation:

A balanced chemical equation is defined as the one that contains same number of atoms on both reactant and product side.

Whereas a chemical reaction that brings change in oxidation state of the reacting species is known as a redox reaction.

When there occurs decrease in oxidation number of an element then it shows the element has been reduced. And, if there occurs an increase in oxidation state of an element then it means the element has been oxidized.

(a)   The reaction between nitrogen and hydrogen to form ammonia will be as follows.

                N_{2} + 3H_{2} \rightarrow 2NH_{3}

So here, oxidation state of nitrogen is changing from 0 to -3. Whereas oxidation state of hydrogen is changing from 0 to +3.

Reaction between ammonia and nitric acid will be as follows.

            NH_{3} + HNO_{3} \rightarrow NH_{4}NO_{3}

Since, it is a combination reaction. Therefore, no change in oxidation state of reacting species is taking place.

(b)  Reaction for conversion of liquid bromine to hydrogen bromide is as follows.

            H_{2}(g) + Br_{2}(l) \rightarrow 2HBr(g)

Here, oxidation state of hydrogen is changing from 0 to +1. Therefore, oxidation of hydrogen is taking place. On the other hand, oxidation state of bromine is changing from zero to -1. Therefore, reduction of bromine is taking place.

(c)   Reaction between Zn and S will be as follows.

               Zn(s) + S(s) \rightarrow ZnS(s)    

Here, oxidation state of zinc is changing from 0 to +2. Hence, oxidation of zinc is taking place.

Oxidation state of sulfur is changing from 0 to -2. Therefore, reduction of sulfur is taking place.

7 0
3 years ago
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