\left[x \right] = \left[ 5\right][x]=[5]2(x+1)/−2 = 8−2 _________
_________ Simplifying
\left[x \right] = \left[ 2\right][x]=[2] = x + 1 + -4
x = -5
Answer: About
Step-by-step explanation:
The missing figure is attached.
Notice in the first picture that Alberta has a complex shape.
You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.
Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.
The area of the trapezoid can be calcualted with the formula:

Where "h" is the height, "B" is the long base and "b" is short base.
And the area of the rectangle can be found with the formula:

Wkere "l" is the lenght and "w" is the width.
Then, the apprximate area of Alberta is:

Substituting vallues, you get:

Therefore, the area of of Alberta is about
.
(6, 2 )
substitute x = 5 into the equation and solve for y
6y + 8 = 20 ( subtract 8 from both sides )
6y = 12 ( divide both sides by 6 )
y =
= 2
the ordered pair is (5, 2 )
Answer:
5^12
Step-by-step explanation:
index notation rules states that when there is a power inside AND outside the brackets, they shall multiply together. hence, we will multiply 3 and 2 so we will get 6 and thus the answer will be 5^6. Sike, that's not the answer, we forgot to multiply 5 with that power too... so we will get 25^6 because same power (outside brackey) will affect everything inside...
now after we got 25^6, we need to simplify it to get 5^n ....
so as we know 5^2 is 25, we can do this,
(5^2)^6 so we will multiply the powers to get
5^12 which is your answer :)
pls mark this as brainliestttt