No,because a Kevin is 7.242971666663E+22 times Smaller than a Joule.
The resistance expected of the heater is 50.1 ohms.
<h3>What is resistance?</h3>
Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).
To calculate the resistance of the heater, we use the formula below.
<h3>Formula:</h3>
- R = V²/P............. Equation 1
Where:
- R = Resistance of the heater
- P = Power of the heater
- V = Voltage supplied to the heater
From the question,
Given:
- V = 480 V
- P = 4.6 kW = 4600 W
Substitute these values into equation 1
- R = (480²)/4600
- R = 50.1 ohms.
Hence, the resistance expected of the heater is 50.1 ohms.
Learn more about resistance here: brainly.com/question/17563681
Answer:
F = M a = M v^2 / R
If v is increased by three the force will be increased by nine,
C) is correct
<span>For this particular problem, we use Ohm's Law. This law deals with the relation between
voltage and current in an ideal conductor. It states that: Potential difference
across a conductor is proportional to the current that pass through it. It is
expressed as V=IR. Using the equation, we can isolate I or the current to one side and the other terms to the other side. We calculate as follows:
V = IR
I = V/R
I = 12 V / 20 </span><span>Ω
I = 0.6 amperes
Therefore, the current that is flowing through the wire supplied with 12 V and having a resistance of 20 </span><span>Ω would be 0.6 amperes.</span>
