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2 years ago

A fixed container containing an ideal gas is heated. The pressure of the gas increases because:_________

1 answer:

5 0

A fixed container containing an ideal gas is heated. The pressure of the gas increases because the molecules move faster.

You can speed up the motion of the molecules in a gas by heating it. The pressure will rise and there will be greater impacts on the container's walls.

The container walls are pressed against by the combined force of the collisions. The energy you provide when you heat the gas makes the gas's particles more kinetically energetic and put more pressure on the container.

As the temperature rises, the pressure must as well since pressure is the force the particles per unit of area exert on the container.

Learn more about pressure and temperature relation here:-

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An engineer is designing a runway. She knows that a plane, starting at rest, needs to reach a speed of 180mph at take-off. If th

kvv77 [185]

Answer:

The plane would need to travel at least $8,\!580\; {\rm ft}$ ( $8.58 \times 10^{3}\; {\rm ft}$ .)

The $10,\!000\; {\rm ft}$ runway should be sufficient.

Explanation:

Convert unit of the the take-off velocity of this plane to $\rm ft\cdot s^{-1}$ :

$\begin{aligned}v &= 180\; {\rm mph} \\ &= 180\; {\rm mi \cdot hrs^{-1}} \times \frac{1\; {\rm hrs}}{3600\; {\rm s}} \times \frac{5280\; {\rm ft}}{1\; {\rm mi}} \\ &= 264\; {\rm ft \cdot s^{-1}}\end{aligned}$ .

Initial velocity of the plane: $u = 0\; {\rm ft \cdot s^{-1}}$ .

Take-off velocity of the plane $v =264\; {\rm ft\cdot s^{-1}}$ .

Let $x$ denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation $x = ((u + v) / 2) \, t$ .

Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration $t$ times average velocity $(u + v) / 2$ .

The distance that the plane need to cover would be:

$\begin{aligned}x &= \left(\frac{u + v}{2}\right)\, t \\ &= \frac{0\; {\rm ft \cdot s^{-1}} + 264\; {\rm ft \cdot s^{-1}}}{2} \times 65.0\; {\rm s} \\ &= 8.58\times 10^{3}\; {\rm ft}\end{aligned}$ .

4 0

3 years ago

what will be the moment of inertia of a body if it rotates at a uniform rate of 10rad/sec^2 by a torque of 120Nm?

Naya [18.7K]

Answer:

12 kgm²

Explanation:

here angular acceleration = 10rad/sec²

torque= 120Nm

moment of inertia=?

we know,

torque= angular acceleration× moment of Inertia

or, moment of inertia = torque/angular acceleration

= 120/10

= 12kgm²

7 0

3 years ago

Aparticlewhosemassis2.0kgmovesinthexyplanewithaconstantspeedof3.0m/s along the direction r = i + j . What is its angular momentu

svetoff [14.1K]

Answer:

$\vec{L}=-30\frac{kgm^2}{s}\hat{k}$

Explanation:

In order to calculate the angular momentum of the particle you use the following formula:

$\vec{L}=\vec{r}\ X\ \vec{p}$ (1)

r is the position vector respect to the point (0 , 5.0), that is:

r = 0m i + 5.0m j (2)

p is the linear momentum vector and it is given by:

$\vec{p}=m\vec{v}=(2.0kg)(3.0m/s)(\hat{i+\hat{j}})=6\frac{kgm}{s}(\hat{i}+\hat{j})$ (3)

the direction of p comes from the fat that the particle is moving along the i + j direction.

Then, you use the results of (2) and (3) in the equation (1) and solve for L:

$\vec{L}=-30\frac{kgm^2}{s}\hat{k}$

The angular momentum is -30 kgm^2/s ^k

8 0

3 years ago

When electrons are lost, a blank ion is formed

Serhud [2]

Answer:

Positive ions, or cations.

3 0

3 years ago

The angle of reflection is the angle the ____ to the reflecting surface.

Arlecino [84]

Answer:

The angle of reflection is the angle the reflected rays make with a perpendicular line to the reflecting surface.

Explanation:

Reflection It is the change of direction suffered by a luminous ray when hitting the surface of an object. The angle of reflection is that which is formed by the reflected ray and the normal vector to the study surface

7 0

3 years ago