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Murljashka [212]
2 years ago
11

About 50 000 years ago, in an area located outside Flagstaff, Arizona, a giant

Physics
1 answer:
Leto [7]2 years ago
7 0

Answer:

F_A =5.625*10^1^6N

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

\triangle E=\frac{1}{2} mv^2 +mgd△E=

2

1

mv

2

+mgd

Having the potential and kinetic energy in place

Mathematically solving for Average forceF_AF

A

\triangle E=F_a*d△E=F

a

∗d

F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}F

A

=

160

1/2∗4.5∗10

7

(20,000)

2

−kg+4.5∗10

7

∗9.81∗160

Therefore Average force F_AF

A

is given by

F_A =5.625*10^1^6N

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Elden [556K]
The answer would be 3,145N. Using W=mg solve for the mass of the man on earth. Once you have the mass you can multiply it by the gravity of Jupiter giving you his weight in Newton’s on Jupiter.
8 0
3 years ago
40 POINTS EASY
11111nata11111 [884]
We know, Mechanical Energy = K.E. + P.E.
As ball is at ground, P.E. would be zero. But as it is in motion, it must have some K.E. and that is:

K.E. = 1/2 mv²
K.E. = 1/2 * 1 * 2²
K.E. = 4/2
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In short, Your Answer would be Option B

Hope this helps!
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3 years ago
How can you decrease the momentum of an object?
mamaluj [8]
You will have to "put force against the object to slow it down." Momentum is the force that is keeping a object moving in a certain direction so if you would want to slow down the object you will have to put another force against the object to slow it down or stop it. For example: a person kicks a ball, the ball moving is the momentum. So, if you would want to stop the ball you would have t put something in its path to slow it down which is the decreasing of it's momentum. Therefore you would put a bump in the wall and when the ball hits the bump it slows down.

Hope this helps!
7 0
3 years ago
Read 2 more answers
A grocery cart with a mass of 15 kg is being pushed at constant speed up a 12∘ ramp by a force FP which acts at an angle of 17∘
Alenkasestr [34]

Answer: a. 198.6J b. - 198.6J

Explanation: Parameters given:

m = 15kg

g = 9.8m/s²

∅ = 12°

a. Work done by the force Fp on the cart if the ramp is 6.5m long.

Given the formula, Fp = Mgsin∅ = 15 x 9.8 x sin12° = 30.56N

Therefore Work done (Wp) = Fp x Ramp Length = 30.56 x 6.5 = 198.64Nm or 198.6J

b. The work done by the force mg on the cart.

Since the cart is being pushed upwards, it acts against gravity with its direction of motion. Taking into account the formula from the previous answer for Work Done (Wg) = Fmg x distance

= 15kg x -9.8m/s² x Sin12° x 6.5m

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4 0
3 years ago
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How much work w is done by the electrostatic force on the moving point charge?
V125BC [204]

As we know that electrostatic force is a conservative force

so we can say by the condition of conservative force

F_c = -\frac{dU}{dr}

here we can rearrange the above equation as

dU = - F_c.dr

now integrate both sides

\int dU = - \int F_c . dr

Now we know by the definition of work done by a force is given by

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W_{EF} = \int F_{e}.dr = - \int dU

so here work done is given as

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