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Murljashka [212]
2 years ago
11

About 50 000 years ago, in an area located outside Flagstaff, Arizona, a giant

Physics
1 answer:
Leto [7]2 years ago
7 0

Answer:

F_A =5.625*10^1^6N

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

\triangle E=\frac{1}{2} mv^2 +mgd△E=

2

1

mv

2

+mgd

Having the potential and kinetic energy in place

Mathematically solving for Average forceF_AF

A

\triangle E=F_a*d△E=F

a

∗d

F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}F

A

=

160

1/2∗4.5∗10

7

(20,000)

2

−kg+4.5∗10

7

∗9.81∗160

Therefore Average force F_AF

A

is given by

F_A =5.625*10^1^6N

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A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.
Mila [183]

Answer:

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Explanation:

From the question we are told that

       The resolution of the telescope is \theta  =  0.00350 \ arc \ second

           The wavelength is  \lambda = 1.70 \mu m = 1.70 *10^{-6} \ m

From the question we are told that

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So      0.00350 \ arc \ second = x

Therefore

             x =  0.00350  *  \frac{1}{3600 }

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The smallest diameter is mathematically represented  as

          D = \frac{1.22 \lambda }{\theta  }

substituting values

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