All categories

3 years ago

Me. Holtsclaw sells his home for $240,000 he must pay the real estate agents a 5% commission. How much is the commission?

Mathematics

1 answer:

grin007 [14]3 years ago

7 0

12000 all you have to do is multiply 240000 by .05 and that is how you find the answer

You might be interested in

A diner has collected data about customer coffee-drinking habits. They have calculated that P(cream) = 0.5, P(sugar) = 0.6, and

zubka84 [21]

For the answer to the question above, asking to determine the P(cream and sugar)
My answer is that you can see that P(sugar not cream) is .2 and P(cream not sugar) is .1 so P(cream and sugar) is .4

I hope my answer helped you.

5 0

2 years ago

Read 2 more answers

(x + 2)(x - 2) helppp

katovenus [111]

2
X - 4 when you use the foil method or multiplication

3 0

3 years ago

Read 2 more answers

Explicit equation for 5,10,20,40

eduard

Answer:

see explanation

Step-by-step explanation:

These are the terms of a geometric sequence with n th term

$a_{n}$ = a $(r)^{n-1}$

Where a is the first term and r the common ratio

r = $\frac{10}{5}$ = $\frac{20}{10}$ = $\frac{40}{20}$ = 2

and a = 5, hence explicit equation is

$a_{n}$ = 5 $(2)^{n-1}$

3 0

2 years ago

What is the measurement of angle A?

Morgarella [4.7K]

Answer:

Step-by-step explanation:

All triangles =180 degrees

180-78 = 102

Since this triangle is an isosceles triangle, that means that 2 sides are the same length, and that 2 angles are the same.

102/2 (you divide by 2 bc the angles unknown are the same measurement) and that equals 51 degrees

7 0

2 years ago

Write the given expression in terms of x and y only. sin(sin−1(x) + cos−1(y))

yan [13]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2308127

_______________

Write the expression below in terms of x and y only:

(I'm going to call it "E")

$\mathsf{E=sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]\qquad\quad(i)}$

Let

$\begin{array}{lcl} \mathsf{\alpha=sin^{-1}(x)}&\qquad&\mathsf{then~-\,\dfrac{\pi}{2}\le \alpha\le \dfrac{\pi}{2}}\\\\\\ \mathsf{\beta=cos^{-1}(x)}&\qquad&\mathsf{then~0\le \beta\le \pi.} \end{array}$

so the expression becomes

$\mathsf{E=sin(\alpha+\beta)}\\\\ \mathsf{E=sin\,\alpha\,cos\,\beta+sin\,\beta\,cos\,\alpha\qquad\quad(ii)}$

• Finding $\mathsf{sin\,\alpha:}$

$\mathsf{sin\,\alpha=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\alpha=x\qquad\quad\checkmark}$

• Finding $\mathsf{cos\,\alpha:}$

$\mathsf{sin^2\,\alpha=x^2}\\\\ \mathsf{1-cos^2\,\alpha=x^2}\\\\ \mathsf{cos^2\,\alpha=1-x^2}\\\\ \mathsf{cos\,\alpha=\sqrt{1-x^2}\qquad\quad\checkmark}$

because $\mathsf{cos\,\alpha}$ is positive for $\mathsf{\alpha\in \left[-\frac{\pi}{2},\,\frac{\pi}{2}\right].}$

• Finding $\mathsf{cos\,\beta:}$

$\mathsf{cos\,\beta=cos\!\left[cos^{-1}(y)\right]}\\\\ \mathsf{cos\,\beta=y\qquad\quad\checkmark}$

• Finding $\mathsf{sin\,\beta:}$

$\mathsf{cos^2\,\alpha=y^2}\\\\
 \mathsf{1-sin^2\,\beta=y^2}\\\\ \mathsf{sin^2\,\beta=1-y^2}\\\\ 
\mathsf{sin\,\beta=\sqrt{1-y^2}\qquad\quad\checkmark}$

because $\mathsf{sin\,\beta}$ is positive for $\mathsf{\beta\in [0,\,\pi].}$

Finally, you get

$\mathsf{E=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}}\\\\\\ \therefore~~\mathsf{sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: inverse trigonometric trig function sine cosine sin cos arcsin arccos sum angles trigonometry

6 0

3 years ago