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2 years ago

Te pico el oyo es que no se si picarte el oyo

Mathematics

1 answer:

Alika [10]2 years ago

7 0

Idk sorry try making a question next time

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Gronala costs $4.50 per pound. Assorted nuts cost $7.00 per pound. how many pounds of granola and nuts are needed to make 7 poun

yulyashka [42]

Let G be the granola we need (in pound)

Let N be the nut we need (in pound)

Trail mix cost $5.00 per pound---> cost for 7 pound = 5 x 7 = $ 35

4.5G+7N= 35

G+ N = 7

Therefore G = 5.6 N=1.4, we would need 5.6 pound granola & 1.4 pound nut

7 0

3 years ago

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Find the length of arc RQ. Use 3.14

Helen [10]

Answer:

The length of arc PQ is 8.1 inches.

Step-by-step explanation:

First, you have to find the angle of POQ. Given that total angles in a circle is 360°, so you have to subtract to get ∠POQ :

$73 + 150 + 65 + ∠POQ = 360$

$288 + ∠POQ = 360$

$∠POQ = 360 - 288 = 72$

Next, you have to apply length of arc formula, Arc = θ/360×2×π×r where θ represents the angle of arc and r is the radius of circle :

$arc = \frac{θ}{360} \times 2 \times \pi \times r$

$let \: θ = 72,\pi = 3.14,r = 6.48$

$arc = \frac{72}{360} \times 2 \times 3.14 \times 6.48$

$arc = 8.1 \: inches \: (near.tenth)$

7 0

3 years ago

Select all of the solutions to the system graphed below.

ra1l [238]

0,-2

4,4

2,0

3,5

Step-by-step explanation:

that was my answer

3 0

3 years ago

Calculus: Help ASAP

wariber [46]

$\bf \displaystyle \int~\cfrac{sec^2(x)}{\sqrt{1+tan(x)}}\cdot dx\\\\
-------------------------------\\\\
u=1+tan(x)\implies \cfrac{du}{dx}=sec^2(x)\implies \cfrac{du}{sec^2(x)}=dx\\\\
-------------------------------\\\\
\displaystyle \int~\cfrac{\underline{sec^2(x)}}{\sqrt{u}}\cdot\cfrac{du}{\underline{sec^2(x)}}\implies \int~\cfrac{1}{\sqrt{u}}\cdot du\implies \int~u^{-\frac{1}{2}}\cdot du
\\\\\\
2u^{\frac{1}{2}}\implies 2\sqrt{1+tan(x)}+C$

6 0

2 years ago

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Write an equation for the following situation:

IRISSAK [1]

Y * x = $300 hope it helps

3 0

3 years ago

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