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NISA [10]
4 years ago
15

50 points What is the value of x?

Mathematics
1 answer:
Korvikt [17]4 years ago
3 0

Answer:

$x=-\frac{38}{9}$

The alternatives are not right.

Just take:

$27(x+4)=-6 \implies 27 \left(-\frac{38}{9} +4\right)=-6 \implies  27 \left(-\frac{38}{9} +\frac{36}{9} \right)=-6 $

$27 \left(-\frac{2}{9}  \right)=-6 \implies -\frac{54}{9}=-6 \implies -6=-6 $

Step-by-step explanation:

27(x+4)=-6

27x+108=-6

27x=-6-108

27x=-114

$x=\frac{-114}{27} $

$x=\frac{-114}{27} $

Multiply denominator and numerator by $\frac{1}{3} $.

$x=-\frac{38}{9}$

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Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
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A group of 11 students have a mean average spelling test score of 7. Another student had a score of 8. What is the mean score of
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7 0
3 years ago
F(x) =5x^2-20x+3 how to find minimum
Leya [2.2K]

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at x=-\frac{b}{2a} . If a is positive, the minimum value of the function is f(-\frac{b}{2a})

f_{min}x=ax^2+bx+c occurs at x=-\frac{b}{2a}

Find the value of x=-\frac{b}{2a}

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

f(2)=5(2)^2-20(2)+3

simplify the result.

f(2)=5(4)-20(2)+3

f(2)=20-40+3

f(2)=-17

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

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3 years ago
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8+5 = 13

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4 years ago
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