Answer:
jfjwbavaskskdbebqlalañskdbxbzbskalakwjdjdjdndndndkdlslsnsnqnqnsbsbsbdbdbd
Answer: plants , water , and rocks
Explanation:
Answer:
0.949367 ≈ 0.95.
Explanation:
The chi square analysis can be done by the formula as follows:
Chi square = (O-E)²/E
Here, O is observed value and E is expected value.
The tall trait follows the Mendel's law, this means the cross between F1 results in the formation of progeny with ratio 3( tall) : 1 (short).
The observed values for set I is 63 tall, 16 short.
The expected value for tall plant = 
= 59.25 .
The expected value for short plant = 
= 19.75.
Put these value in the formula for chi square analysis:
For tall plants = ( 63 - 59.25)²/ 59.25= 0.237.
For short plants = (16 - 19.75)²/ 19.75 = 0.712
Total value for set I = 0.237 + 0.712 = 0.95.
Thus, the answer is 0.95.
Answer:
Considering the <u>whole progeny</u> (100%), there will be
- 25% Black male kittens, XBY
- 0% Calico Male kittens
- 25% Calico female kittens, XBXR
Explanation:
<u>Available data:</u>
- The gene for Calico (multicolored) cats is an x-linked trait and codominant
- Calico Females receive a "B" and an "R" gene, and have black and orange splotches on white coats. Their genotype is XBXR.
- Males can only be black or orange, but never calico. Their genotype is XBY and XRY
Cross: a female calico cat with a black male
Parentals) XBXR x XBY
Gametes) XB XR XB Y
Punnett square) XB XR
XB XBXB XBXR
Y XBY XRY
F1) Among the whole progeny:
- 2/4 = 50% will be black (female XBXB and male XBY)
- 1/4 = 25% will be Calico (female XBXR)
- 1/4 = 25% will be Orange (male XRY)
Among females:
- 1/2 = 50% of females will be black, XBXB
- 1/2 = 50% of females will be Calico, XBXR
Among males:
- 1/2 = 50% of males will be black, XBY
- 1/2 = 50% of males will be orange, XRY
Answer:I believe B:The Phosphate Group
Explanation:
