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Marrrta [24]
3 years ago
13

Would you use the mean or the median to summarize the typical weight of a pumpkin in this contest?

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0
I would use the median
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Which equation has the steepest parabola?
ICE Princess25 [194]

Given:

The equations of parabolas in the options.

To find:

The steepest parabola.

Solution:

We know that, if a parabola is defined as

(y-k)=n(x-h)^2

Then, the greater absolute value of n, the steeper the parabola.

It can be written as

\dfrac{1}{n}(y-k)=(x-h)^2

p(y-k)=(x-h)^2

where p=\dfrac{1}{n}, the smaller absolute value of p, the steeper the parabola.

Now, find the value of |p| for eac equation

For option A, |-0.5|=0.5

For option B, |5|=5

For option C, |8|=8

For option D, |-10|=10

Since, the equation is option A has smallest value of |p|, therefore, the equation (x+2)^2=-0.5(y+3) represents the steepest parabola.

Hence, the correct option is A.

7 0
3 years ago
Infinity - infinity?
pav-90 [236]
Do you mean what does infinity + infinity equals to? If so, infinity + infinity = infinity.
3 0
3 years ago
Write 420 as a product 9f prime numbers​
stich3 [128]

Answer:

2, 2, 3, 5, 7 that is the farthest you can go

Step-by-step explanation:

2,2,3,5,7 prime factorization of 420 but impossible to get 9 factors

5 0
3 years ago
Write a word problem for y=10/x
Bess [88]

Answer: farmer ted has ten tomatoes and needs to divide them among five people how many tomatoes does each person get?

Use the equation y = 10/x for your answer.

X = the 5 people and y = the amount of tomatoes

4 0
3 years ago
How do I simplify the n^-6*n^3 topic "Negative and Zero Exponents"
Alchen [17]
Since you’re multiplying n^-6 and n^3, you can add the exponents: -6+3 = -3

n^-6 * n^3 = n^-3

If you need to finish without having a negative exponent in your answer, then remember a negative exponent means that factor is on the wrong side of the fraction.

n^-3 = n^-3 / 1 = 1/n^3

when the factor moves to the other side of the fraction, the side of the exponent changes.
7 0
3 years ago
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