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SSSSS [86.1K]
3 years ago
14

The measures of two angles are 4 x ° and ( 2 x + 12 ) ° . What must be true if x = 13 ?

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

4x degrees= 52 degrees

(2x+12) degrees= 38 degrees

Step-by-step explanation:

4(13)=52

(2(13)+12)=38

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14) x - 27 0<br> 3<br> X^3-27=0<br> X^3-27=0
Inessa [10]

Answer:

For the top equation, x = 27 (I think you meant to put x - 27 = 0. If not, I can always edit my answer for you)

For the bottom, x = 3

Hope this helps! Have a grrrreat day lol

5 0
3 years ago
Write the standard equation of the circle with the given Center and radius:
Kipish [7]

9514 1404 393

Answer:

  B.  (x +4)² +(y +5)² = 64

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

Filling in your given values, you have ...

  (x -(-4))² +(y -(-5))² = 8²

Simplifying, you get ...

  (x +4)² +(y +5)² = 64 . . . . . . . matches choice B

_____

<em>Additional comment</em>

As you learn more different "standard form" equations, it may be helpful to keep a list, along with reminders of what the variables stand for and how the equation is used.

5 0
3 years ago
Every year,students at Memorial High school volunteer to clean local highway roadsides. Each club or team at the school is
arlik [135]
She has to clean 2.5
8 0
3 years ago
Read 2 more answers
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
Solve for x rounded to the nearest hundredth: 10 - 3x = 5
igomit [66]

Answer:

x = 5/3

Step-by-step explanation:

You ALWAYS want your term to be by itself!! So what you need to do is move your constant away from it.

Step 1: Adjust as needed, subtract 10 from both sides of your equation. It should end up like this.

-3x = 5 - 10

Step 2: Solve as needed before continuing equation.

-3x = -5

Step 3: Now you need to get your term by itself. You should divide -3 on both sides of your equation so you should get something like this.

x = -5 / -3

Step 4: You're basically done now! Just simplify! NEGATIVES CROSS EACH OTHER OUT!!!

x = 5/3 OR 1.6

<em>KEY:</em>

<em>Negative and Negative = Positive</em>

<em>Negative and Positive = Negative</em>

<em>Positive and Positive = Positive</em>

4 0
3 years ago
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