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Zarrin [17]
3 years ago
6

Write an assembly subroutine that check if a number is in the interval of [0, 10] and return 1 if the number is in this interval

and 0 otherwise. Call this subroutine to check if each integer in an array in the memory is in this interval and write the results of all numbers into another array in the memory
Computers and Technology
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

.data

array: .word 1,3,5,7,9,11,13,15,17,19

result: .word 0,0,0,0,0,0,0,0,0,0

.text

  la $s0, array

  la $s1, result

  addi $t0, $zero, 0

  INTERVAL:  bge $t0, 10, END

     sll $t1, $t0, 2

     add $t2, $s0, $t1

     lw $t2, 0($t2)

     jal LIMIT

     IF:    bne $a0, 1, ELSE

        add $t3, $s1, $t1

        sw $t2, 0($t3)

     ELSE:

     addi $t0, $t0, 1

     j INTERVAL

  END:    

  addi $v0, $zero, 10

  syscall

  LIMIT:  

     addi $a0, $zero, 0

     START: bge $t2, 0, NEXT

        b ENDLIMIT

     NEXT:  ble $t2, 10, SET

        b ENDLIMIT  

     SET:   addi $a0, $zero, 1

     ENDLIMIT:

     jr $ra

Explanation:

The assembly source code is used to create a subroutine called "INTERVAL" that checks if a number from an array is in a range of 1 to 10. The program returns 1 if the condition is met but 0 if otherwise.

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Homework 8 Matlab Write a function called fibonacciMatrix. It should have three inputs, col1, col2, and n. col1 and col2 are ver
Amiraneli [1.4K]

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>end</em>

<em>end</em>

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>elseif n<1</em>

<em>    v = 0;</em>

<em>end</em>

<em>function [n] = abcd(x)</em>

<em>if (x == 1 || x==0)</em>

<em>    n = x; </em>

<em>    return</em>

<em>else</em>

<em>    n = abcd(x-1) + abcd(x-2);</em>

<em>end</em>

<em>end</em>

<em>fibonacci = [0 1];</em>

<em>for i = 1:n-2</em>

<em>    fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];</em>

<em>end</em>

<em>>> myfib(8)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13</em>

<em>>> myfib(10)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13   21   34</em>

See more about python at  brainly.com/question/18502436

8 0
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