I am almost 100% sure that it is called a microprocessor
Answer:
The answer to this question can be given as:
Method:
public static void showTwos(int number) //method definition.
{
method body.
System.out.print(number + " = "); //print number
while (number % 2 == 0) //condition
{
System.out.print("2 * "); //print message.
number = number / 2;
}
System.out.println(number); //print value.
}
Explanation:
In the above method definition firstly, we declare the method showTwos() that name is already given in the question then we pass a variable number as a parameter in the method. In this first, we take input number from the user and pass into this method. In this method we use a while loop it is an entry control loop in this loop first we modules the number if it is equal to 0.Then we divide the number by 2 and in the last, we print the value.
The correct answer to the question is option D.
A good number of desktop publishers would rather create the text portion of their documents using a word processing program, and then import the text into a desktop publishing file. Thankfully, w<span>ord processing programs are compatible with desktop publishing and other software programs.</span>
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
Answer:
#include <iostream>
using namespace std;
int main()
{
int side1=0;
int side2=0;;
int side3=0;
cout <<"Enter side one measurement";
cin >> side1;
cout <<"Enter side two measurement";
cin >> side2;
cout <<"Enter side three measurement";
cin >> side3;
if(side1+side2>side3||side1+side3>side2||side2+side3>side1){
if (side1==side2 && side2==side3)
{
cout <<"equilateral triangle"<<endl;
}
else if(side1==side2||side2==side3||side1==side3){
cout <<"Isosceles triangle"<<endl;
}
else{
cout <<"scalene triangle"<<endl;
}
}else{
cout<<"No triangle";
}
return 0;
}
Explanation:
The code is written in c++. It takes measurements of each side from users as input and check the types of triangle based on the following formula.
1. Equilateral Triangle
If all sides of a triangle are equal than it's an equilateral triangle.
2. Isosceles Triangle
If any two sides of a triangle are equal than it's an Isosceles triangle.
3. Scalene Triangle
If all the sides of a triangle are of different length than it's an Scalene triangle.
In a triangle the sum of two sides is greater than third side otherwise it's not a triangle.