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satela [25.4K]
3 years ago
10

Solve 300 xq+n for x 10 POINTS! PLEASE ANSWER HONESTLY!!! i will report if u don’t!

Mathematics
2 answers:
viva [34]3 years ago
7 0
X= n + 300
----------------
q
tamaranim1 [39]3 years ago
4 0
You can't just report people if they are wrong. People make mistakes.
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A package of twelve eggs cost $5 at this price, how much does each individual egg cost?
dimulka [17.4K]

Answer:

About 0.42

Step-by-step explanation:

To find the answer You first have to divided because you have to find how much does one egg cost.

$5 divided by 12 = 0.41666666666 Round to 0.42

Therefore one individual egg cost  about 0.42

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2 years ago
I will give Brainly ! help please its geometry I will give brainly <br> Thank you for your time.
Cerrena [4.2K]

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I guess reflexive property........

4 0
2 years ago
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What are the coordinates of the point on the directed line segment from (1,-5) to
Black_prince [1.1K]

Answer:

Q (2.5, -4)

Step-by-step explanation:

Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5

AQ = (x - 1, y + 5)

QC = (10 - x, 1 - y)

AQ:QC = 1:5

so 5*AQ = QC

5(x - 1) = (10 - x)

5(y + 5) = 1 - y

Solve them:

5x - 5 = 10 - x

6x = 15

x = 15/6 = 2.5

5y + 25 = 1 - y

6y = -24

y = -24/6 = -4

Then answer is Q (2.5, -4)

6 0
2 years ago
The base is a 45 45 90 triangle with a leg of 5 in. The height is 1.8 what’s the volume of the prism
hjlf
brainly.com/question/3774542 Try this it might help
6 0
3 years ago
The supreme shipping company can load trucks with both rectangular and cylindrical containers. A rectangular container has a vol
soldi70 [24.7K]

the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Let x be the number of rectangular containers and y the number of cylindrical containers.

Since a rectangular container has a volume of 100 ft ³and weighs 200 pounds and a cylindrical container has a volume of 200 ft.³ and weighs 100 pounds, and each truck has room for at most 4200 ft.³ of containers and can carry a maximum of 4800 pounds,

We have that the maximum volume of the truck V = 100x + 200y.

Also, the maximum weight of the truck is W = 200x + 100y

Since V = 4200 ft.³  and W = 4800 pounds,

100x + 200y = 4200 and 200x + 100y = 4800

x + 2y = 42 (1) and 2x + y = 48 (2)

Multiplying (1) by 2 and (2) by 1, we have

2x + 4y = 84 (3) and 2x + y = 48 (4)

Subtracting (4) from (3), we have

2x + 4y = 84

-

2x + y = 48

3y = 36

y = 36/3

y = 12

Substituting y into (1), we have

x + 2y = 42

x + 2(12) = 42

x + 24 = 42

x = 42 - 24

x = 18

Also, since the shipping company charges $60 for a rectangular container and $55 for a cylindrical container, the income, P = 60x + 55y

Since x = 18 and y = 12, the maximum income is P = 60x + 55y

= 60(18) + 55(12)  

= 1080 + 660

= $1740

So, the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Learn more about maximum income here:

brainly.com/question/24559594

3 0
3 years ago
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