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coldgirl [10]
3 years ago
13

What is 0.36 (6 is repeating) expressed as a fraction in simplest form?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0
11/30 is .36666... because that is what you get when you divide 11 by 30. Hope this helps!
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2. Round the following numbers to the nearest 10 thousand:
Vlad [161]

The  values of the given numbers when it is rounded up to the nearest 10 thousands are:

  • 990000
  • 150000

<h3>What is rounding up in mathematics?</h3>

Rounding up can be described as the process that is been used in the mathematics which is been used in the estimation of a particular number in a context.

It should be noted that in rounding the  a number up, it is required to look at the next digit at the right hand of the given figures in a case whereby the digit is less than 5,the digit can be rounded down, but in the case whereby the digit is more that 5 then it can be rounded up .

From the given values, we are given the 990,201 and 159,994  and if this were to rounded up to the nearest 10 thousand then we will start from the right hand sides and round down the values less than 5 and round up the values that is more that 5. and their values will be 990000

and 150000.

Read more about rounding up at:

brainly.com/question/28324571

#SPJ1

8 0
1 year ago
Simplify the complex fraction. x+4x/y/7/3x
lora16 [44]
I hope this helps la la la

3 0
3 years ago
Read 2 more answers
When is the product of two nonzero integers less than or equal to both of the two factors
aleksley [76]
The answeris equall to because they are the same #
5 0
3 years ago
If X and Y are independent continuous positive random
Leni [432]

a) Z=\frac XY has CDF

F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy

where the last equality follows from independence of X,Y. In terms of the distribution and density functions of X,Y, this is

F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy

Then the density is obtained by differentiating with respect to z,

f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy

b) Z=XY can be computed in the same way; it has CDF

F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Differentiating gives the associated PDF,

f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Assuming X\sim\mathrm{Exp}(\lambda_x) and Y\sim\mathrm{Exp}(\lambda_y), we have

f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}

and

f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0
3 years ago
If x and y are 2 complementary angles then find the value of y if measure of angle x is 20 degree
schepotkina [342]

Answer:

y=70 degrees

Step-by-step explanation:

If 2 angles are complimentary, they add up to 90 degrees.

x+y=90 degrees

x=20 degrees

y=90-20 degrees

y=70 degrees

If that is wrong, try this. Let's say the questions gives us the fact that x is 20 degrees greater than y.

y=x

Substituting x for y, the equation is x+x+20=90

Since y is x, x would also be y, which is 35. then x+20 would be 55.

So y would be 35.

THE ANSWER WOULD BE <u><em>70 DEGREES</em></u>, BUT IF THAT IS WRONG, DO THE SECOND ONE, WHICH IS 35

6 0
3 years ago
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